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Dafna11 [192]
3 years ago
9

A sample of Freon-12 (CF2Cl2) occupies 25.5 L at 298 K and 153.3 kPa. Find its volume at STP.

Chemistry
1 answer:
tangare [24]3 years ago
6 0

35.8 L  
According to the combined gas law: pV=nRT 
p=pressure
 V=volume
 T=temperature in Kelvin
 R=the universal gas constant
  n=number of moles of the gas
 
 Rearranging the equation: n= pV/RT
 n=(153.3kPa)(25.5L)/R(298K)= 13.1/R 
 At STP (standard temperature and pressure) p=100kPa and T=273.15K. 

 Rearranging the equation again: V=nRT/p V=[(13.1/R)(R)(273.15K)]/100kPa = 35.8L

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What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?
Lubov Fominskaja [6]

Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})

Hence, the probability of finding the particle in the  one-dimensional box is:

P = \int_{x_{1}}^{x_{2}} \psi^{2} dx

P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx

P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]

P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})    

Solving for n=4:

P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})    

P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})    

P = \frac{1}{8}

I hope it helps you!

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3 years ago
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