trees are important in maintaining air quality, because they act like a filter, drawing particles from the air

when holden goes to visit phoebe, how does she react to his arrival? how are the two similar and how are they different?

monitta

Catcher in the Rye is a young-adult fiction by J. Salinger. It is a novel based on the coming of the age and literary realism. Phoebe is disappointed with Holden's vindication.

Holden Caulfield is the protagonist and the narrator of the story who is intelligent but is expelled from the school. Phoebe is Holden's sister, she is infuriated by Holden's dismissal.

She knows that their father would be angry because Holden is expelled from school. Holden tries to explain his situation to his sister and tells her about his minimum chance of joining the military school.

He explains to her how bad is his school Pencey and he dislikes that place. But Phoebe interrupts him by saying that he doesn't like anything or anywhere.

Her challenge makes him think about the one thing that he likes the most and he couldn't. It shows Phoebe's concern to stimulate Holden. She is seen sympathetic and angry with her brother for not growing up.

Holden describes them in loving, caring terms, demonstrating his genuine affection and respect for them. How does Holden characterize Phoebe? Holden describes Phoebe as wise, overly affectionate at times, and overly emotional for her age.

Also as smart, tiny, and a little noisy. Holden, Phoebe, and Allie are siblings in the novel "The Catcher in the Rye." Holden looks up to his younger brother and sister as idealized versions of himself. Holden describes Allie as the most intelligent and pleasant member of his family.

To know more about the Holden, refer: brainly.com/question/1344932

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4 0

1 year ago

Given the reaction: N2 + O2 = 2NO for which the Keq at 2273 K is 1.2 x 10-4

MAXImum [283]

Answer:

(a): The expression of equilibrium constant is $K_{eq}=\frac{[NO]^2}{[N_2][O_2]}$

(b): The equation to solve the concentration of NO is $[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}$

(c): The concentration of NO is 0.0017 M.

Explanation:

The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term $K_{eq}$

(a):

The given chemical equation follows:

$N_2+O_2\rightarrow 2NO$

The expression for equilbrium constant will be:

$K_{eq}=\frac{[NO]^2}{[N_2][O_2]}$

(b):

The equation to solve the concentration of NO follows:

$[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}$ ......(1)

(c):

Given values:

$K_{eq}=1.2\times 10^{-4}$

$[N_2]_{eq}=0.166M$

$[O_2]_{eq}=0.145M$

Plugging values in equation 1, we get:

$[NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}$

$[NO]=\sqrt{2.88\times 10^{-6}}$

$[NO]=0.0017 M$

Hence, the concentration of NO is 0.0017 M.

3 0

3 years ago

You discover a chemical reaction that produces 1 moles of valuable propane for every 6 moles of carbon supplied.

Greeley [361]

Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.

From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.

From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.

Thus from 1.8 moles of C we can obtain $\frac{1}{6}$ ×1.8 = 0.3 moles of the propane can be prepared.

Thus the amount of propane produced in this reaction is determined.

8 0

3 years ago

When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H

Debora [2.8K]

Answer:

$Y=58.15\%$

Explanation:

Hello,

For the given chemical reaction:

$Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)$

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

$n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3$

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

$n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3$

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

$m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3$

Finally, we compute the percent yield with the obtained 2.10 g:

$Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%$

Best regards.

7 0

3 years ago

Which is the main source of dissolved oxegyn in the ocean

kolezko [41]

Answer:phytoplankton

Explanation:

6 0

3 years ago