The volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³
<h3>
What is volume?</h3>
Volume is known to be equal to the mass divided by the density.
It is written thus:
Volume = Mass / density
<h3>
How to calculate the volume</h3>
The volume is calculated using the formula:
Volume = mass ÷ density
Given the mass = 0. 10g
Density = 4.51 g/cm³
Substitute the values into the formula
Volume of titanium = 0. 10 ÷ 4.51 = 0. 02 cm³
Thus, the volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³
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Answer:
c. CH4 < NH3 because the NH bond is more polar than the CH bond.
Explanation:
Actually, the electronegativity difference between carbon and hydrogen is just about 0.4. This meager difference in electronegativity corresponds to a nonpolar bond between the two atoms.
However, the electronegativity difference between nitrogen and hydrogen is about 0.9. This larger electronegativity difference corresponds to the existence of a polar covalent bond between the two atoms.
Hence the N-H bond is significantly polar unlike the C-H bond. This implies that CH4 molecules are only held together by weak dispersion forces while NH3 molecules are held together by stronger dipole-dipole interactions and hydrogen bonds.
Molarity can be defined as the number of moles of substance dissolved in 1 L of solution.
In the given question ,
number of LiOH moles - 1.495 mol
Dissolved volume - 750 mL
molarity is calculated for 1 L = 1000 mL
In 750 mL - 1.495 mol of LiOH is dissolved
Therefore in 1000 mL - 1.495 mol / 750 mL x 1000 = 1.99 mol
Answer:
1. When you first opened the bottle of coke the pressure of gas in the coke (increased) and the dissolved gas(leaves) the coke. 2. When you placed the coke in hot water , the pressure of gas in the coke (increased) and the dissolved gas(leaves) the coke 3. Therefore to increase the solubility of a gas in a liquid ( that is to make a gas more soluble in a liquid.
Explanation:
Hope it helps.
Answer:
The balanced equation is :
Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)
