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ValentinkaMS [17]
3 years ago
6

How was Bohr's atomic model different from those of previous scientists?

Physics
1 answer:
exis [7]3 years ago
4 0

Answer:Bohr placed the electrons in distinct energy levels.  Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantised orbits.

Explanation: also rutherfords was just a hypothesis while Bhor took the time to make his an experiment

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A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above
nydimaria [60]

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

Explanation:

From the question we are told that

   The mass of the rock is  m = 0.250 \ kg

    The length of the string is  L = 0.75 \  m

    The angle the string makes horizontal is  \theta  = 11.9^o

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  \phi = 34.6^o

    The angular velocity of the rock is  w = 2.50 rev/s  = 2.50 * 2\pi  =15.7 \ rad/s

Generally the radius of the circle made by the length of the string is mathematically represented as

               r = L cos(\theta )

=>            r = 0.75  cos(11.9 )

=>            r = 0.734 \ m

Generally the resultant tangential velocity is mathematically represented as

      v__{R}}  = w * r

=>  v__{R}}  = 15.7  *0.734

=>  v__{R}}  =  11.5 \ m/s

Generally the tangential velocity along the x-axis is  

      v_x  = -v__{R}} *  sin(\phi)

=>   v_x  =- 11.5 *  sin(34.6)

=>   v_x  = -6.543 \ m/s

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      v_y = v__{R}} *  cos(\phi)

=>   v_y  = 11.5 *  cos(34.6)

=>   v_y  = 9.47 \ m/s

Generally the tangential velocity along the y-axis is  

      v_z = v__{R}} *  cos(90)

=>   v_z = 0 \ m/s

Generally the tangential velocity at that instant is mathematically represented as

       v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

8 0
3 years ago
Current what can do work in an electric device
Serggg [28]
It could help transport important information
5 0
3 years ago
A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball above the ground t seconds af
Vilka [71]

Answer:

V = (-32t +32) ft/s

The velocity of the bowling ball after t seconds is the time derivative of the position function s(t). To obtain the velocity from s(t) we simply differentiate s(t) with respect to t. That is

V = ds(t)/dt = -16×2t + 32×1 = -32t + 32.

When differentiating, you multiply the coefficient of each term in the equation with the power of the variable and then reduce the power by 1 just like above.

Explanation:

8 0
3 years ago
What would be the average fixed cost per unit at an activity level of 5,200 units? assume that this level of activity is within
Vitek1552 [10]

The average fixed cost per unit at an activity level of 5,200 units is $6.00.

<h3>What is the average fixed cost?</h3>

The average fixed cost (AFC) is fixed cost that does not change with the change in the number of goods and services produced by a company. To put it in a nutshell, average fixed cost (AFC) is the fixed cost per unit and is calculated by dividing the total fixed cost by output level.

Since no cost is fixed for a long time, average fixed cost is only for a short run. When units of production increase, the average fixed cost per unit decreases. Similarly, when the business produces less units, average cost increases per unit.

However, only one unit, mostly capital, is fixed. Examples of average fixed cost are the salaries of permanent employees, mortgage payment on machinery and plant, rent, more.

Average Fixed Cost Formula:

AFC = Total fixed cost/Output (Q)

To know more about plant visit: brainly.com/question/22167412

#SPJ4

4 0
2 years ago
a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s . part a calculate its total kinet
erma4kov [3.2K]

49 J   is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.

Given:    m = 7.3 Kg ;  r = 9.4 cm = 0.094 m   ;   v = 3.1 m

Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation  + Kinetic energy due to translation

i,e     KE = 1/2*m*v2   +   1/2*I*ω2      where   I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity

Now for pure rotation (without slipping)    v = rω  

also for the ball (solid sphere)  I = 2/5*m*r2

Hence our kinetic energy becomes  

 KE = 1/2*m*v2 +  1/5*m*v2 = 7/10*m*v2

so   KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J

Learn more about kinetic energy here

brainly.com/question/12669551

#SPJ4

5 0
1 year ago
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