1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dybincka [34]
3 years ago
10

In a few sentences, compare and contrast pressurized water reactors and boiling water reactors.

Physics
2 answers:
kondaur [170]3 years ago
6 0
For pressurized water reactors the coolant is not permitted to boil in the core of the PRW, however the coolant in boiling water reactors is permitted to do so in the core of BWR. Pressurized water reactors have an indirect cycle. Whereas, the boiling water reactors go through a direct cycle. Both are light water reactors. 
Mama L [17]3 years ago
5 0

Explanation:

The main difference between the pressurized water reactors and boiling water reactors is in the process of generation of steam. A boiling water reactor uses a single water circuit to produce steam directly while a pressurized  water reactor produces steam indirectly using two water circuits. In a boiling water reactor steam is directly produced by boiling the water coolant while in pressurized reactor the heat from the reactor core is used.

You might be interested in
2 H2O2-> 2H20+02
Luden [163]

Answer:

This reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen. Add 2 molecules of hydrogen peroxide and 2 molecules of water. Since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

3]Explanation: This reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen. Add 2 molecules of hydrogen peroxide and 2 molecules of water. Since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

4]Two moles of hydrogen peroxide H2O2 decomposes to produce two moles of water H2O and one mole of oxygen gas O2(g) , which then bubbles off

6 0
2 years ago
Why do tin roofs make creaking sounds on hot days?
laiz [17]

Answer: Yes, on many slate-roofed homes as temperatures change, such as cooling at night or heating during the day, thermal expansion or contraction of the slates may cause movement that in turn causes snapping, popping, or cracking noises, even bangs and clanks or clicks from the roof.

Explanation:

8 0
3 years ago
Read 2 more answers
A 1451 kg car is traveling at 48.0 km/h. How much kinetic energy does it possess? K.E. =
jarptica [38.1K]

           Kinetic energy  =  (1/2) (mass) (speed)²

BUT . . . in order to use this equation just the way it's written,
the speed has to be in meters per second.  So we'll have to
make that conversion.

        KE  =  (1/2) · (1,451 kg) · (48 km/hr)² · (1000 m/km)² · (1 hr/3,600 sec)²

               =  (725.5) · (48 · 1000 · 1 / 3,600)²  (kg) · (km·m·hr / hr·km·sec)²

               =  (725.5) · ( 40/3 )²  ·  ( kg·m² / sec²)

               =    128,978  joules  (rounded)
8 0
3 years ago
A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
Calculate the resistance of an electric bulb which allows a 10 A current when connected to a 220 V power source
kodGreya [7K]

Resistance can be calculated by Ohm's law

As per ohm's law we will have

V = i * R

here we will have

voltage = 220 volts

current = 10 A

So by the above formula we will have

220 = 10* R

R = 22 ohm

So resistance of the bulb is 22 ohm.

4 0
3 years ago
Other questions:
  • The volume of a cylindrical tin can with a top and a bottom is to be 16π cubic inches. If a minimum amount of tin is to be used
    14·1 answer
  • How many neutrons and electrons are in ruthenium??? PLEASE HELP IM DROWNING IN WORK!!!!!
    8·2 answers
  • Which moon phase happens next after a new moon
    9·2 answers
  • Hydrogen gas was cooled from 150c to 50c. its new volume is 75.0 ml. what was its original volume
    5·1 answer
  • Which of the following statements are incorrect? a) The state of matter for an object that has a definite volume but not a defin
    9·1 answer
  • If a fertilized egg cannot reach the uterus, what is the most likely result?
    8·2 answers
  • An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in
    15·1 answer
  • 20 points please helppp me I’m begging u this is due soon please come on ????? Anyone
    6·2 answers
  • 3. What is the equation for the mechanical advantage of a lever?
    8·1 answer
  • Describe What is the shape of a velocity time graph for an object with constant acceleration
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!