Answer:
306.8264448 m
47.0016 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Distance traveled by car
![s_c=ut+\dfrac{1}{2}at^2\\\Rightarrow s_c=\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s_c%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s_c%3D%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Distance traveled by truck
![s_t=ut](https://tex.z-dn.net/?f=s_t%3Dut)
In order to overtake both distances should be equal
![\dfrac{1}{2}at^2=ut\\\Rightarrow \dfrac{1}{2}at=u\\\Rightarrow t=\dfrac{2u}{a}\\\Rightarrow t=\dfrac{2\times 23.5}{3.6}\\\Rightarrow t=13.056\ s](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7Dat%5E2%3Dut%5C%5C%5CRightarrow%20%5Cdfrac%7B1%7D%7B2%7Dat%3Du%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B2u%7D%7Ba%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B2%5Ctimes%2023.5%7D%7B3.6%7D%5C%5C%5CRightarrow%20t%3D13.056%5C%20s)
![s_c=\dfrac{1}{2}at^2\\\Rightarrow s_c=\dfrac{1}{2}3.6\times 13.056^2\\\Rightarrow s_c=306.8264448\ m](https://tex.z-dn.net/?f=s_c%3D%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s_c%3D%5Cdfrac%7B1%7D%7B2%7D3.6%5Ctimes%2013.056%5E2%5C%5C%5CRightarrow%20s_c%3D306.8264448%5C%20m)
The distance the car has to travel is 306.8264448 m
![v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 3.6\times 306.8264448+0^2}\\\Rightarrow v=47.0016\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2as%2Bu%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%203.6%5Ctimes%20306.8264448%2B0%5E2%7D%5C%5C%5CRightarrow%20v%3D47.0016%5C%20m%2Fs)
The speed of the car when it overtakes the truck is 47.0016 m/s
Answer:
a) E₀ = 2.125 eV, b) # photon2 = 9.2 10¹⁵ photons / mm²
Explanation:
a) To calculate the energy of a photon we use Planck's education
E = h f
And the ratio of the speed of light
c = λ f
We replace
E = h c /λ
Let's calculate
E₀ = 6.63 10⁻³⁴ 3 10⁸/585 10⁻⁹
E₀ = 3.40 10⁻¹⁹ J
Let's reduce
E₀ = 3.4 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)
E₀ = 2.125 eV
b) Let's look for the energy in each pulse
P = E / t
E = P t
E = 20.0 0.45 10⁻³
E = 9 10⁻³ J
let's use a ratio of proportions (rule of three) if we have the energy of a photon (E₀), to have the energy of 9 10⁻³ J
# photon = 9 10⁻³ /3.40 10⁻¹⁹
# photon = 2.65 10¹⁶ photons
Let's calculate the areas
Focus area
A₁ = π r²
A₁ = π (3.4/2)²
A₁ = 9,079 mm²2
Area requested for calculation r = 1 mm
A₂ = π 1²
A₂ = 3.1459 mm²
Let's use another rule of three. If we have 2.65 106 photons in an area A1 how many photons in an area A2
# photon2 = 2.65 10¹⁶ 3.1459 / 9.079
# photon2 = 9.2 10¹⁵ photons / mm²
It tells us the number of protons that are present in the nucleus, the positively charged region of that atom.
Answer:
A. the pancake that forms is a different state of matter.
Explanation:
because the pancake mix is liquid ,and when you cook it you for a solid.