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larisa86 [58]
3 years ago
6

A biker goes up hill with a constant speed of 10km/h. Then he goes downhill with a constant speed of 50km/h. What's his average

speed
Physics
1 answer:
Sladkaya [172]3 years ago
4 0

This is not as simple as it looks.  

His average speed is NOT (10km/hr + 50km/hr)/2 = 30 km/hr.

You have to use the definition of speed:

Speed = (total distance covered) / (time to cover the distance).

Let's say the distance up (and down) the hill is 'd' .

Then the time it takes to go up the hill is (d/10) hours.

And the time it takes to come down the hill is (d/50) hours.

Total distance = 2d km

Total time = (d/10) + (d/50) = (5d/50) + (d/50) = 6d/50

Speed = distance/time = 2d/(6d/50) = 100d/6d

<em>Speed = </em>100/6 = <em>16-2/3 km/hr</em>

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In the periodic table, the properties repeat in what direction?​
pogonyaev

Answer:

Left to right and top to bottom

Explanation:

On the periodic table, the properties repeat from left to right and from top to bottom.

Periodic properties have a pattern from the top to the bottom or down a group or family.

Also, across the period from left to right, they also show a repeating pattern.

  1. Certain properties increase from left to right and decreases from top to bottom. E.g. electronegativity.
  2. Also, some properties decreases from left to right and increases from top to bottom e.g. atomic radius.
7 0
3 years ago
What is the focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index 1. 2?
Fed [463]

The focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index  1.2 will be 18.4 m

The focal length of a lens is determined when the lens is focused at infinity. Lens focal length tells us the angle of view—how much of the scene will be captured—and the magnification—how large individual elements will be.

Focal length of a lens is the distance between center of lens and focal point . Focal point is a point on principal axis , at which light rays parallel to principal axis meet after refraction through lens or seem to meet after refraction .

The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature. The sign convention for focal length and radius of curvature is the same.

focal length = 2 * radius of curvature

given

radius of curvature = 9.2 m

focal length = 2 * 9.2

                    = 18.4 m

To learn more about focal length here

brainly.com/question/16188698

#SPJ4

4 0
2 years ago
A Ford Mustang weighs about 3500 pounds, and can accelerate from 0-60 MPH in about 5 seconds. What force is responsible for this
Hunter-Best [27]

We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.

m = 3500lb = 1587.57kg

The values of the velocities are,

\text{Initial Velocity} = V_i = 0

\text{Final Velocity} = V_f = 60mph = 26.822m/s

We know that the acceleration is equivalent to the change of the speed in a certain time therefore

a = \frac{v_f-v_i}{t}

a = \frac{26.822-0}{5}

a = 5.36m/s^2

Now applying the Newton's second law we have,

F= ma

F = (1587.57)(5.36)

F = 8516.36N

Therefore the approximate magnitude is 8516.36N

5 0
3 years ago
How much potassium nitrate, KNO3, would completely dissolve in 100g of water at 40℃?
const2013 [10]
Ok I know this from other stuff potassium nitrate would completely dissolve in a 100 g on was at 30 c would be 60 but this is 40 so I’m not really sure and I don’t what to ok give you a bad grade but if I had to guess I would go with 65 grams
8 0
3 years ago
In the year 2000, a company made $4.7 million in profit. For each consecutive year after that, their profit increased by 15%. Ho
olya-2409 [2.1K]

Answer: $8.2 million.

Explanation:

If we have a quantity A, and we have an increase of x%, this can be written as:

A + (x%/100%)*A

Now, for this particular case we have:

In year 2000 (we can define this year as the year zero, y = 0) the initial value is $4.7 million.

The next year, y = 1, there is an increase of 15%, then we will have a profit of:

P = $4.7 million + (15%/100%)*$4.7 million = $4.7 million +  0.15*$4.7 million

P = $4.7 million*(1 + 0.15) = $4.7 million*(1.15)

in the next year, y = 2, the profit will be:

P =  $4.7 million*(1.15) + (15%/100%)* $4.7 million*(1.15)

  = $4.7 million*(1.15) + 0.15* $4.7 million*(1.15)

   = $4.7 million*(1.15)^2

We already can see the pattern, the profit in the year y will be:

P(y) = $4.7 million*(1.15)^y

In particular, in the year 2004 we have y = 4, then the profit that year will be:

P(4) = $4.7 million*(1.15)^4 = $8.2 million.

8 0
3 years ago
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