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3 years ago

Calculate the percent by mass of each element in

1 answer:

3 0

The elements present in Ammonium Nitrate are Hydrogen, Nitrogen, and Oxygen at a ratio of 4:2:3, respectively. Hydrogen weighs in at 1.008 amu, Nitrogen at 14.007, and Oxygen at 15.999. This means that the molar mass would be:

Hydrogen
4 x 1.008 = 4.032 amu

Nitrogen
2 x 14.007 = 28.014 amu

Oxygen
3 x 15.999 = 47.997 amu

Total
4.032 + 28.014 + 47.997 = 80.043 amu

The molar mass of Ammonium Nitrate is 80.043 grams per mole.

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What is the electronic configuration of Au3+?

Anettt [7]

Answer:

$AU^{3+} : [Rn] 5f^3$

Explanation:

Writing electronic configuration of any element you should know atomic number of that element ,

and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital

and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.

writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.

$AU : [Rn] 5f^3 6d^1 7s^2$

remove three electron from outer most shell of AU

$AU^{3+} : [Rn] 5f^3$

4 0

3 years ago

Explain why you get a basic solution when you dissolve NaF in water.

SashulF [63]

Answer:

That's because in water NaF will dissolve to produce Na+,the conjugate base of a strong acid which will not react with water.however F- will behave like a bronsted base, and accept a proton from water.this is called hydrolysis reaction, because a molecule of water is broken up.

a conjugate base is what I leftover after an acid loses a hydrogen ion.

I hope this helps

5 0

3 years ago

A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40

Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = $40 hr/week\times 8 week = 320 hours$

The concentration of xylene in the workplace = $40 \mu g/m^3$

The worker is inhaling air at a rate of $0.9 m^3/hr$ .

Amount xylene inhaled by worker in an hour :

= $40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr$

Amount xylene inhaled by worker in 320 hours:

$36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg$

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

$\frac{24}{320}\times 11.520 mg=0.864 mg$

Assuming 70 kg body mass, the chronic daily intake of xylene :

$\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day$

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0

2 years ago

5. What happens to the average kinetic energy of water molecules as water freezeslt decreases as the water absorbs energy from i

4vir4ik [10]

The correct answer among the choices listed above is option D. The average kinetic energy of water molecules as water freeze decreases as water releases energy to its surroundings. Energy is released as the molecules go into a more condensed phase which is the solid.

3 0

2 years ago

Read 2 more answers

You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the

Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0

2 years ago