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Andrew [12]
3 years ago
11

What relationship exists between two variables when their ratio is a constant? a negative slope a direct proportion an inverse p

roportion
Chemistry
2 answers:
Verdich [7]3 years ago
6 0
Direct proportion

Hope this helps (:
melisa1 [442]3 years ago
5 0

Answer:

a direct proportion

Explanation:

Boyle’s law is an example of direct proportion

PV = K, at constant temperature

where P is pressure, V is volume and K is a proportionality constant.  

According to Boyle’s law the two variables pressure and volume are directly proportional to each other. When pressure increases volume increases and vice-versa.  

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Define the term inertia
n200080 [17]

Answer:

Explanation:

Enertia is an integral part of Newton's first law of motion.

It is the tendency of an object to <u>stay at rest</u> or <u>to continue moving</u> until and unless <u>any external unbalanced force</u>, (like, applied force or force of tension or frictional force ) is applied to either move it from rest or change its speed(in other words, accelerate it!!).

Example below, is of ball at rest (fig1) and if this ball is moving straight on a frictionless surface(like ice) it will keep moving!! until, we push it or pull it.

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3 years ago
Which type of fermentation occurs in yeast?
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Fermentation occur in yeast is alcoholic.
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3 years ago
A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu
klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}

<u>T₂ = 19.95°C</u>

6 0
3 years ago
A common demonstration in chemistry courses involves adding a tiny speck of manganese(IV) oxide to a concentrated hydrogen perox
Nuetrik [128]

Answer:

2H_{2}O_{2} ---> 2H_{2}O + O_{2}

2,2,1 being the coefficients

Explanation:

These type of question rely on the person answering the question knowing the formula of hydrogen peroxide. Hydrogen peroxide has a formula that is very similar to that of water except it has a two after the O, which makes it very easy to remember.

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Within a conventional light bulb,
aniked [119]

Answer:

D

Explanation:

Solid, Liquid and Gas are the states of matter. Light is neither a solid, a liquid, nor a gas.

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