Find the solution set for y = 2x + 1, given the replacement set {(-2, -3), (-1, -1), (0, 2), (1, 3), (2, 6)} ...?
1 answer:
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Answer:
x1= 14/4 and X2 = -2
Step-by-step explanation:
To find the values of "X" for which when the function is evaluated gives 19 we need to equal the function to 19, as follows:
2x^2+3x+5 = 19
2x^2+3x+5-19=0
2x^2+3x-14=0
Then, solving for "x" we need to use the quadratic formula (Attached), where a, b, and c, are the following:
a: 2 b: 3 c: 14
Using the quadratic formula, we get:
x1= 14/4 and X2 = -2
