am sorry i thout this was my question not your answer sorry
The final position of the object after 2 s is 11 m.
Motion: This can be defined as the change in position of a body.
⇒ Formula:
- x = x₀+v₀t+1/2(at²)........................ Equation 1
⇒ Where:
- x = Final position of the object
- x₀ = Starting position
- v₀ = Starting velocity
- t = time
- a = acceleration
From the question,
⇒ Given:
- x₀ = 4.5 m/s
- t = 2 s
- x₀ = 2m
- a = 0 m/s²
⇒ Substitute these values into equation 1
- x = 2+(4.5×2)+1/2(0²×2)
- x = 2+9+0
- x = 11 m
Hence, The final position of the object after 2 s is 11 m
Learn more about motion here: brainly.com/question/15531840
Answer:
Jupiter and Saturn
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Your book has applied the chain rule to produce:
dv/dt = dv/dx * dx/dt
Now, we can get dv/dx by:
1) Differentiate
x = vt, with respect to v.
dx/dv = t
Now, if we take the inverse of this, we can obtain dv/dx
dv/dx = 1/t
This is also proven by the fact that dv/dx is the change in velocity and if you multiply it by dv/dx, which is equivalent to dividing by the change in time, as we just proved, then you obtain acceleration.
To solve this problem it is necessary to apply the concepts related to pressure as a unit that measures the force applied in a specific area as well as pressure as a measurement of the density of the liquid to which it is subjected, its depth and the respective gravity.
The two definitions of pressure can be enclosed under the following equations
![P = \frac{F}{A}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BF%7D%7BA%7D)
Where
F= Force
A = Area
![P = \rho gh](https://tex.z-dn.net/?f=P%20%3D%20%5Crho%20gh)
Where,
Density
g = Gravity
h = Height
Our values are given as,
![d = 0.8m \rightarrow r = 0.4m](https://tex.z-dn.net/?f=d%20%3D%200.8m%20%5Crightarrow%20r%20%3D%200.4m)
![A = \pi r^2 = \pi * 0.4^2 = 0.503m^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%20%2A%200.4%5E2%20%3D%200.503m%5E2)
If we make a comparison between the lid and the tube, the diameter of the tube becomes negligible.
Matching the two previous expressions we have to
![\frac{F}{A} = \rho g h](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7BA%7D%20%3D%20%5Crho%20g%20h)
Re-arrange to find h
![h = \frac{F}{A\rho g}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7BF%7D%7BA%5Crho%20g%7D)
![h = \frac{390}{(0.503)(1000)(9.8)}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B390%7D%7B%280.503%29%281000%29%289.8%29%7D)
![h = 0.079m](https://tex.z-dn.net/?f=h%20%3D%200.079m)
![h = 7.9cm](https://tex.z-dn.net/?f=h%20%3D%207.9cm)
Therefore the height of water in the tube is 7.9cm