To solve the problem, use Kepler's 3rd law :
T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
but first covert 6.00 years to seconds :
6.00years = 6.00years(365days/year)(24.0hours/day)(6...
= 1.89 x 10^8s
The radius of the orbit then is :
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓
= 6.23 x 10^11m
the mass would remain the same and the weight would change. mass defines the actual amount of an object, while weight is the force gravity has on that object. gravity is different on the moon and the earth therefore the weight will change
Answer:
11:10 will be the time. reflection causes the object to be flipped when you see its image at the mirror
