What is the frequency of a wave if the wave speed is 24 m/s and the wavelength is 2m?

Calculate the change in entropy when 1.00 kg of water at 100 âˆ˜c is vaporized and converted to steam at 100 âˆ˜c. Assume that t

pickupchik [31]

Answer:6.04 kJ/K

Explanation:

Given

mass of water $m=1 kg$

Latent heat of vaporization is $L=2256\times 10^{3} J/kg$

entropy at constant temperature is given by

$\Delta S=\frac{Q}{T_0}$

$Q=m\times L$

$Q=1\times 2256\times 10^3$

$\Delta s=\frac{2256\times 10^3}{100+273}$

$\Delta s=6.04kJ/K$

5 0

4 years ago

1) Why do the different rocks exposed in the Grand Canyon appear in layers for the most part? Where are the oldest layers of roc

fiasKO [112]

This is what i put:

<span> The Grand Canyon is made up of sedimentary rock; over time, sediments formed into layers. The layers on the bottom are the oldest, and the layers on the top are the youngest and newest.

Try and paraphrase though</span>

5 0

3 years ago

When the starter motor on a car is engaged, there is a 300 A cunent in the wires between the bauery and the motor. Suppose the w

docker41 [41]

Answer:

diameter of transmission is 3.473 mm

Explanation:

given data

current = 300 A

total wire length = 1.0 m

voltage drop = 0.55 V

solution

as here Resistivity of copper is = 1.68 × $10^{-8}$ ohm- m

so we get here resistance of wire that is

resistance = $\frac{V}{I}$ ..............1

R = $\frac{0.55}{310}$

R = 1.774 × $10^{-3}$ ohm

and now we get diameter of wire that is

R = $\frac{\rho l}{A}$ .............2

$\pi \frac{d^2}{4} = \frac{\rho l}{R}$

d² = $\frac{4\rho l}{\pi R}$ ...............3

put here value

d² = $\frac{4\times 1.68\times 10^{-8} \times 1}{\pi \times 1.774\times 10^{-3}}$

d = $\sqrt{12.064\times 10^{-6}}$

d = 3.473 × $10^{-3}$ m

d = 3.473 mm

so diameter of transmission is 3.473 mm

4 0

4 years ago

Two positive point charges, each of which has a charge of 2.5 × 10−9 C, are located at y = + 0.50m and y = − 0.50m. Find the mag

Salsk061 [2.6K]

Answer:

The resultant electric force is 14.8N to the right.

Explanation:

Since the three charges aren't in the same line, we have to break down the force in components. First, we need to know the distance from the third charge to the other ones. That is made using the Pythagorean Theorem. As the figure is symmetric with respect to the x-axis, the two distances are the same:

$r=\sqrt{(0.50m)^{2}+(0.70m)^{2}}=0.86m$

Now, we use the Coulomb's Law to obtain the magnitude of the individual forces caused by each charge on the third charge:

$|F_{13}|=k\frac{q_1q_3}{r^{2}} \\\\|F_{13}|=(9*10^{9}Nm^{2}/C^{2})\frac{(2.5*10^{-9}C)(3.0*10^{-9}C)}{(0.86m)^{2}}\\\\|F_{13}|=9.1N$

For the same reason the distances are the same, the magnitude of the forces are the same:

$|F_{23}|=|F_{13}|=9.1N$

So, to get the resultant force, we have to break down this forces in components. To do this, we need their angles with respect to the x-axis. Let θ₁ and θ₂ be these angles, respectively. Then, we calculate them using trigonometry:

$\theta_1=\arctan(\frac{-0.50m}{0.70m})=-35.5\°\\\\\theta_2=\arctan(\frac{0.50m}{0.70m})=35.5\°$

Now, we calculate the components of the forces:

$F_{13}_x=F_{13}\cos\theta_1=9.1N\cos(-35.5\°)=7.4N\\\\F_{13}_y=F_{13}\sin\theta_1=9.1N\sin(-35.5\°)=-5.3N\\\\F_{23}_x=F_{23}\cos\theta_2=9.1N\cos(35.5\°)=7.4N\\\\F_{23}_y=F_{23}\sin\theta_2=9.1N\sin(35.5\°)=5.3N$

Evidently, the y-components cancel out, and the resultant electric force on the third charge is $7.4N+7.4N=14.8N$ along the x-axis (to the right, because it's positive).

8 0

3 years ago

A stone tumbles into a mine shaft strikes bottom after falling for 4.2 seconds. How deep is the mine shaft

ziro4ka [17]

$d = u \times t \: + \frac{1}{2} \times a \times {t}^{2}$
Since initial velocity is zero hence , u = 0

=> d = 1/2 * a * t2

$d = 0.5 \times 9.8 \times {4.2}^{2}$
on solving we get

d = 86.436 metres

Note ; Here Gravitational Acceleration is take as , g = 9.8 m/s2

3 0

3 years ago