Answer:
254.5 K
Explanation:
Data Given
initial volume V1 of neon gas = 12.5 L
final Volume V2 of neon gas = 10.5 L
initial Temperature T1 of neon gas = 30 °C
convert Temperature to Kelvin
T1 = °C +273
T1 = 30°C + 273 = 303 K
final Temperature T2 of neon gas = ?
Solution:
This problem will be solved by using Charles' law equation at constant pressure.
The formula used
V1 / T1 = V2 / T2
As we have to find out Temperature, so rearrange the above equation
T2 = V2 x T1 / V1
Put value from the data given
T2 = 10.5 L x 303 K / 12.5 L
T2 = 254.5K
So the final Temperature of neon gas = 254.5 K
Answer:
The new volume of the balloon be
.
Explanation:
We have,
Initial volume is 556 cm ³
The temperature of the balloon decreases from 278 K to 231 K.
We need to find the new volume of the balloon if the pressure is constant.
The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.
, P is constant


So, the new volume of the balloon be
.