Answer:
okay so lets say i drop a ball that weighs 2 pounds off a building and a ball that ways 1 pound off the building at the same time the lighter ball would hit the ground first because its lighter and so they heavier it is the slower it drops the lighter it is the faster it drops
Explanation:
Explanation:
The chemical equation is as follows.
And, the given enthalpy is as follows.
; = 102.5 kJ
Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol
Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.
102.5 =
102.5 =
102.5 - 12 =
x = 181 kJ
Now, total bond enthalpy of per mole of ClO is calculated as follows.
x =
= 339.5 - 243
= 96.5 kJ
Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.
3 millimeters is the rock
Answer:
I think it would it spider
Explanation:
Spider catch there meals in there web then suck the blood out after it wraps them up in webing
Answer:
See explanation below
Explanation:
The question is incomplete. However, here's the missing part of the question:
<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>
<em>C(s) + 2H2(g) <--> CH4(g). </em>
<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>
With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.
The expression of Kp for this reaction is:
Kp = PpCH4 / (PpH2)²
We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:
PpCH4 = Kp * PpH2²
*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.
Now solving for PpCH4:
PpCH4 = 0.455 * (1.78)²
<u><em>PpCH4 = 1.44 atm</em></u>