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3 years ago

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Chemistry

2 answers:

lawyer [7]3 years ago

7 0

Answer:

( B, C, E, F)

Explanation:

Person above is right!

But I hope this helps!!

agasfer [191]3 years ago

4 0

Answer:

2,3,5,6

Explanation:

i got it right

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Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)

Reptile [31]

Answer: The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]$

For the given chemical reaction:

$C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]$

We are given:

$\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J$

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0

3 years ago

PLEASE HELP DUE IN 30 MINUTES NO LINKS PLEASE

hammer [34]

Answer:

B is the correct answer

Explanation:

If this answer is correct plzz mark me as brainliest plzzzz

7 0

3 years ago

What is the sum of 16+ -20?

mr Goodwill [35]

Answer:

-4

Explanation:

PLz give me brainliest I worked hard thank u

6 0

3 years ago

Read 2 more answers

What would happen to the pressure if the volume were reduced to 0.5 l and the temperature increased to 260 ∘c?

Vsevolod [243]

The ideal gas law. PV=nRT pressure x volume = moles x Faraday's constant x Temp Kelvin (C+273) Original data Pressure 1 atmosphere Volume 1 liter Temp 25C = 298K New data Volume 0.5 liter pressure X Temp 260C = 533K P1v1T1 = P2v2T2 plug and chug. (1)(1)(293) = (x)(0.5)(533) Solve for X, which is the new pressure.

8 0

3 years ago

Pls answer this question and have a AMAGING day!! :))

ladessa [460]

Answer:

Explanation:

because it is being cooled down

hoped this helps

3 0

3 years ago