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mote1985 [20]
3 years ago
13

I need help on 12 what do u do

Chemistry
1 answer:
pickupchik [31]3 years ago
4 0
Benzene at the same prssure ie the horizontal dotted line, benzene requires the minimal temperature hence its most volatile
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Can you solve the anagrams
slamgirl [31]
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7 0
3 years ago
Which trends appear as the elements in Period 3 are considered from left to right?
andreev551 [17]

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

8 0
3 years ago
At what pH range bayer process operate? and why?
Novosadov [1.4K]

Explanation:

Bayer process is industrial method of the refining of the bauxite to produce alumina which is aluminum oxide.

As alumina is amphoteric in nature, it exhibits a higher solubility at both the extremes of pH range, it is possible to dissolve alumina in low as well as in high pH solutions.

Dissolution of the alumina at high pH is well recognized in Bayer process. Bauxite is digested in very <u>high pH solution (> 13)  of alkali</u> like sodium hydroxide at temperature of about 150–250°C and pressure at 20 atm. <u>This is done so that the dissolved alumina is separated from rest of insoluble bauxite minerals. </u>

3 0
3 years ago
How many grams of lead(II) iodide are produced from 6.000 moles of NaI according to the balanced equation: Pb(NO3)2 + 2 NaI à 2
marta [7]

Answer:

mass PbI₂ formed = 1383 grams

Explanation:

Pb(NO₃)₂ + 2NaI => 2NaNO₃ + PbI₂(s)

6 mol NaI =>  1/2(6 mol) PbI₂ = 3 mol PbI₂ x 461.01 g/mol = 1383.03 grams ≅ 1383 grams (4 sig. figs.)

7 0
3 years ago
2 H2+O2=2 H2O
tia_tia [17]

Answer:

The percent yield is about 66.6%, but with sig figs it's 70%

Explanation:

The formula for percent yield is: (Actual Yield/Theoretical Yield) * 100

1. In order to solve for percent yield, you need both an actual and theoretical yield. This problem gives us an actual yield for H2O, which is 75 grams. Great, you're halfway there!

2. Next, you need to solve for the theoretical yield. In order to do so, you need to set up your stoichiometric ratio.

100g O_{2}  * (\frac{1 mol O_{2} }{31.998g O_{2} } )*(\frac{2 mol H_{2}O }{1 mol O_{2} } )*(\frac{18.015gH_{2}O }{1 mol H_{2}O } ) = 112.6g H_{2}O

a) Take your given 100g of O2 and first convert it to moles

b) Then take the O2 in moles and create your mole-to-mole ratio. You're only given 2 values (75g of H2O and 100g of O2), so you know to use O2 and H2O in your ratio. The coefficients are essentially your ratio, so for H2O to O2 it's 2:1

c) Then convert the value from the mole-to-mole ratio back into grams to get your theoretical yield (as values from mole ratios are in moles)

3. Now that you have both your actual and theoretical yields, you can plug it into the equation and solve.

\frac{Yield_{Actual} }{Yield_{Theoretical} } * 100 = \frac{75}{112.6} = 66.60403646

Which is 66.6% when rounded. With sig figs, again, it is 70%

5 0
3 years ago
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