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Tems11 [23]
2 years ago
12

Lucky charms A. Element B. Compound C.Homogeneous Solution D.Heterogeneous​

Chemistry
1 answer:
LUCKY_DIMON [66]2 years ago
3 0

Answer:

b I think if it's wronged sorry

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To measure the amount of nickel in some industrial waste fluid, an analytical chemist adds sodium hydroxide solution to a sample
Cloud [144]

Answer:

The final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

Explanation:

It is given that sodium hydroxide is added to collect the solid nickel(II) hydroxide product

The empirical equation for this statement is

Ni2+ + NaOH --> Ni (OH)2 + Na+

We will first balance the hydroxide molecule. On the right side there are two OH molecules.

Thus, on the left side we will take 2 sodium hydroxide

Ni2+ + 2NaOH --> Ni (OH)2 + Na+

Now we will balance the sodium ion which are 2 in numbers on the left side and 1 on the right side

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

So, the final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

8 0
3 years ago
1-<br> the<br> Nalt and Gil-<br> Cu2+<br> ad out- <br> what are the spectator ions in this reaction
Mrac [35]

Answer:

cu2 is 5he correct answer

3 0
1 year ago
What is the definition of <br> incandescence?
Vilka [71]

Answer:

the emission of visible light by a body, caused by its high temperature.Compare luminescence.

the light produced by such an emission.

the quality of being incandescent.

5 0
2 years ago
What is the chemical formula for hydrogen peroxide?
Anon25 [30]
Chemical formula is H2O2
7 0
2 years ago
4.41 g of propane gas (C3H8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below
gayaneshka [121]

Answer :  The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

q_{rxn}=-q_{cal}

q_{cal}=c_{cal}\times \Delta T

where,

q_{rxn} = heat released by the reaction = ?

q_{cal} = heat absorbed by the calorimeter

c_{cal} = specific heat of calorimeter = 97.1kJ/^oC=97100J/^oC

\Delta T = change in temperature = (T_{final}-T_{initial})=(27.282-25.000)=2.282^oC

Now put all the given values in the above formula, we get:

q_{cal}=(97100J/^oC)\times (2.282^oC)

q_{cal}=221582.2J=221.6kJ

As, q_{rxn}=-q_{cal}

So, q_{rxn}=-221.6kJ

Thus, the heat of the reaction is -221.6 kJ

6 0
3 years ago
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