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3 years ago

Heat engines use heat to do work. true or false.

2 answers:

7 0

Heat engines transform heat energy to other type of energy, typically mechanical or electrical, so yeah, they use heat to work.

ankoles [38]3 years ago

4 0

True.

Heat engines makes use of heat to do work.

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Part CPart complete Determine the maximum force P that can be applied without causing the two 43-kg crates to move. The coeffici

Wewaii [24]

Answer:

the maximum force will be equal to 134.84 N

Explanation:

We have given mass m = 43 kg

Coefficient of static friction $\mu _s=0.32$

Acceleration due to gravity $g=9.8m.sec^2$

We have to find the maximum force which , when applied there is no movement of crates

This maximum force will be equal to frictional force

Frictional force is given by $f=\mu mg=0.32\times 43\times 9.8=134.84N$

So the maximum force will be equal to 134.84 N

3 0

3 years ago

In a rectangular coordinate system, a positive point charge q = 6.50 nC is placed at the point x=0.190 m ,y=0, and an identical

son4ous [18]

Answer:

A) x and y components of the electric field (Ep) at the origin.

Epx = -1620.5 N/C

Epy = -1620.5 N/C

Ep = (1620.5(-i)+1620.5(-j)) N/C

B) Magnitude of the electric field (Ep) at the origin.

Ep= 2291.7 N/C

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/d²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

d: distance from charge q to point P in meters (m)

Equivalence

1nC= 10⁻⁹C

Data

K= 9x10⁹N*m²/C²

q₁ = q₂= +6.5nC=+6.5 *10⁻⁹C

d₁=d₂=0.190m

Graphic attached

The attached graph shows the field due to the charges:

Ep₁ : Electric Field at point P (x=0, y=0) due to charge q₁. As the charge q₁ is positive (q₁+) ,the field leaves the charge.

Ep₂: Electric Field at point P (x=0, y=0) due to charge q₂. As the charge q₂ is positive (q₂+) ,the field leaves the charge

Ep: Total field at point P due to charges q₁ and q₂.

Because q₁ = q₂ and d₁ = d₂, then, the magnitude of Ep₁ is equal to the magnitude of Ep₂

Ep₁ = Ep₂ = k*q/d² = 9*10⁹*6.5*10⁻⁹/0.190m² = 1620.5 N/C

Look at the attached graphic :

Epx = Ep₁= -1620.5 N/C

Epy = Ep₂= -1620.5 N/C

A) x and y components of the electric field (Ep) at the origin.

Ep = (1620.5(-i)+1620.5(-j)) N/C

B) Magnitude of the electric field (Ep) at the origin.

$E_{p} =\sqrt{1620.5^{2}+1620.5^{2} } = 2291.7 \frac{N}{C}$

8 0

3 years ago

Why did Isaac Newton come up with the three laws of motion

son4ous [18]

He turned his observations into laws, to establish constants and explanations of future scientists.

3 0

4 years ago

The areas of the pistons are 20 cm^2 and 100 cm^2. A force of 10 N is applied to the small piston. How much force is on the larg

strojnjashka [21]

Answer:

50N

Explanation:

A1 (area of the smaller piston) = 20cm² = 0.2m²

F1 (force acting on the smaller piston) = 10N

F2 (force acting on the larger piston) =?

A2 (area of the larger piston) = 100cm² = 1m²

F1 / A1 = F2 / A2

F2 = (F1*A2) / A1

F2 = (10*1) / 0.2

F2 = 50N

3 0

4 years ago

Which characeristic makes omasis different from diffusion.

Ksju [112]

<span>haha I used to think biology was so hard, i find it quite easy now.
Okay, so basically Osmosis is the movement of water molecules from a higher concentration to a lower concentration. Diffusion is generally the movement of a gradient from higher concentration to an area of lower concentration. Osmosis applies to water only, whereas diffusion, you have many types such as Passive transport [ movement of molecules from high- low, NO CELLULAR ENERGY needed! ] then you have faciliated diffusion ( basically uses a channel protein to allow big substances to go through the membrane : NO ENERGY needed]
OSMOSIS, the important thing to remember is that water ALWAYS flow towards the region with the higher concentration of the solute (ex: Salt is solute, water is solvent) solute is the thing that is being dissolved. Solvent is the one doing the dissolving. Hope this helped!</span>

5 0

4 years ago