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3 years ago

Heat engines use heat to do work. true or false.

2 answers:

7 0

Heat engines transform heat energy to other type of energy, typically mechanical or electrical, so yeah, they use heat to work.

ankoles [38]3 years ago

4 0

True.

Heat engines makes use of heat to do work.

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Describe one unique/different food from Israel

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Answer:

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Burekas.Explanation:

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3 years ago

Read 2 more answers

Why are the meters squared in the formula to calculate acceleration?

lianna [129]

Answer:

During acceleration, you are moving across a distance over a time, but also increasing how fast we are doing it. Therefore, it means by how many meters per second the velocity changes every second

Explanation:

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4 years ago

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

SOVA2 [1]

Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

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4 years ago

What is the definition of the coefficient of kinetic friction?

Nookie1986 [14]

The coefficient of kinetic friction is the force between two objects when one object is moving, or if two objects are moving against each other

4 0

4 years ago

Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. How long will you measure it to be if

Rashid [163]

Answer:

264 m

Explanation:

The complete question is

Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. How long will you measure it to be if it flies past you at a speed of v = 0.75c

using the length contraction relationship,

$l = l_{0} \sqrt{1 - \beta ^{2} }$