Answer
for every meters it will go up 15 so if it was 2 secoonds it woudl be 30 and if it was 3 seconds it would be 45 meters
Explanation:
Answer:
Moon
Explanation:
although the moon is by far the smallest mass of the listed bodies, it is also by far the closest.
Flow chart of a system is a diagrammatic representation of how that system performs it's functions.
<h3>The flow chart of internal combustion engine</h3>
The flow chart of internal combustion engine is the diagrammatic representation of how the engine works.
The inlet valve of the engine is the valve that allows for the entry of fuel-air mixture into the engine.
The exhaust valve of the engine is the allows for the outflow of used gases from the engine.
From the attached flow chart, Intake valves are opened to allow the flow of an air/fuel mixture into the engine's cylinders prior to compression and ignition, while exhaust valves open to permit the expulsion of exhaust gases from the combustion process after ignition has occurred.
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Answer:
The velocity of the police car is, v = 17.798 m/s
Explanation:
Given data,
The actual frequency of the siren, f = 2010 Hz
The observed frequency of siren is, f' = 2120 Hz
The velocity of the observer, v' = 0 m/s
The velocity of the source, v = ?
The formula for Doppler effect,

Where,
V - velocity of sound waves in air.

Substituting the given values,

v = 17.798 m/s
Hence, the velocity of the police car is, v = 17.798 m/s
We are given the following:
Bobo's swimming speed = 2.0 m/s
Width of the river = 100 m
Flowrate of the river = 6.0 m/s due east
First, we need to illustrate the problem. Draw the river with a width of 100 meters. Then, the flow of the river, east at 6 meters per second. Lastly, draw Bobo at one side of the river facing north and an arrow representing swimming speed at 2 meters per second.
Now, we can use the Pythagorean theorem to solve this rate problem.
c^2 = a^2 + b^2
c = speed of Bobo needed
a = speed of Bobo facing north
b = flow rate of the river going east
c^2 = 2^2 + 6^2
c = 6.32 m / s should be his speed to overcome the current and make a landing at the desired location.