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Sergeu [11.5K]
3 years ago
10

When water waves meet, they can combine to form new waves. In constructive waves, a ________ amplitude wave is formed. In destru

ctive waves, a wave with a __________ amplitude is formed. A) greater, smaller B) smaller, greater C) smaller, smaller D) greater, greater
Physics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

In constructive waves, a <u><em>greater</em></u> amplitude wave is formed. In destructive waves, a wave with a <u><em>smaller</em></u> amplitude is formed. (option A)

Explanation:

Interference is called the superposition or sum of two or more waves. Depending mainly on the wavelengths, amplitudes and the relative distance between them, there are two types of interference: constructive or destructive.

Constructive interference occurs when there are two waves of identical or similar frequency (both have motions equal to an even number of similar wavelengths) and overlap the peak of one with the peak of the other. These effects add together and make a wave of greater amplitude. All of this is possible because the waves were in the same phase in the beginning (in the same position).

Destructive interference occurs in the opposite case to constructive. When the crest of one wave overlaps the valley of the other, they cancel out since they are in different phases when they overlap (they were in different positions). That is, as in the case of constructive waves they were added, in the case of destructive waves they cancel out (subtract).

So, <u><em>In constructive waves, a greater amplitude wave is formed. In destructive waves, a wave with a smaller amplitude is formed. </em></u>

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An unknown mass of each of the following substances, initially at 23.0, absorbs 1910 of heat. The final temperature is recorded
babymother [125]
The data not given here is the specific heat capacity of pyrex glass equal to 0.75(J/g  °C). In this case, heat is equal to mass x specific heat capacity x temperature rise. Temperature difference is then equal to 1910 J / 0.75 J/g  °C / 23 g equal to 110. 75  <span>°C </span>
3 0
3 years ago
Strong forces
sdas [7]

Strong forces:

- are forces holding nucleons together

- are independent of electric charge

- act only over a very short distance

So, correct answer is 4) all of these

Explanation:

The strong force is one of the 4 fundamental forces of nature. It is responsible for holding the nucleons (protons and neutrons) together into the nucleus of the atom.

In fact, the protons inside the nucleus of an atom experience a repulsive, electrostatic force between each other: if this force was not balanced, the protons will simply fly away from each other, and the nucleus would break apart, so no nucleus could exist.

The strong force acts to prevent this effect: the strong force is attractive at such short scales, and it holds the protons and the neutrons together. It is independent of the electric charge: in fact, it acts in the same way on protons and neutrons, being attractive in both cases. Also, the strong force acts only over very short distances, so it acts only inside the nucleus of an atom.

Therefore, all the statements are correct, so the correct option is

4) all of these

#LearnwithBrainly

6 0
3 years ago
The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 rpm. These
alexdok [17]

Answer:

θ  = 6.3 *10³ revolutions

Explanation:

Angular acceleration of the drill

We apply the equations of circular motion uniformly accelerated

ωf= ω₀ + α*t  Formula (1)

Where:  

α : Angular acceleration (rad/s²)  

ω₀ : Initial angular speed ( rad/s)  

ωf : Final angular speed ( rad

t :  time interval (s)

Data

ω₀ = 0

ωf = 350000 rpm = 350000 rev/min

1 rev = 2π rad

1 min= 60 s

ωf = 350000 rev/min =350000*(2π rad/60 s)

ωf = 36651.9 rad/s

t = 2.2 s

We replace data in the formula (2) :

ωf= ω₀ + α*t

36651.9 = 0 + α* (2.2)

α = 36651.9 / (2.2)

α = 17000 rad/s²

Revolutions made by the drill

We apply the equations of circular motion uniformly accelerated

ωf²= ω₀ ²+ 2α*θ Formula (2)

Where:  

θ : Angle that the body has rotated in a given time interval (rad)

We replace data in the formula (2):  

(ωf)²= ω₀²+ 2α*θ

(36651.9)²= (0)²+ 2( 17000 )*θ

θ = (36651.9)²/ (34000 )

θ  = 39510.64 rad = 39510.64 rad* (1 rev/2πrad)

θ  = 6288.31 revolutions

θ  = 6.3 *10³ revolutions

3 0
4 years ago
What is the equivalent resistance of the
BigorU [14]

Answer:

Approximately 111\; {\rm \Omega}.

Explanation:

It is given that R_{1} = 200\; {\Omega} and R_{2} = 250\; {\Omega} are connected in a circuit in parallel.

Assume that this circuit is powered with a direct current power supply of voltage V.

Since R_{1} and R_{2} are connected in parallel, the voltage across the two resistors would both be V. Thus, the current going through the two resistors would be (V / R_{1}) and (V / R_{2}), respectively.

Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor: I = (V / R_{1}) + (V / R_{2}).

In other words, if the voltage across this circuit is V, the total current in this circuit would be I = (V / R_{1}) + (V / R_{2}). The (equivalent) resistance R of this circuit would be:

\begin{aligned} R &= \frac{V}{I} \\ &= \frac{V}{(V / R_{1}) + (V / R_{2})} \\ &= \frac{1}{(1/R_{1}) + (1 / R_{2})}\end{aligned}.

Given that R_{1} = 200\; {\Omega} and R_{2} = 250\; {\Omega}:

\begin{aligned} R &= \frac{1}{(1/R_{1}) + (1 / R_{2})} \\ &= \frac{1}{(1/(200\: {\rm \Omega})) + (1/(250\; {\rm \Omega}))} \\ &\approx 111\; {\rm \Omega}\end{aligned}.

7 0
2 years ago
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