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Nikitich [7]
10 months ago
5

hydrogen decomposes quickly when exposed to light. the reaction for decomposing hydrogen peroxide is:

Chemistry
1 answer:
Svet_ta [14]10 months ago
5 0

The decomposition reaction for hydrogen peroxide is given below:

                                     2H_{2} O_{2} → 2H_{2} O + O_{2}

This is a decomposition reaction.

Reactions in which a reactant breaks into two or more products are known as Decomposition reactions.

                                          AB → A + B

here, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction

The decomposition reaction of decomposing hydrogen peroxide is exothermic. When the hydrogen peroxide undergoes a decomposition reaction, heat is also released along with water and oxygen.

Hence the  reaction for decomposing hydrogen peroxide is :

         2H_{2} O_{2} → 2H_{2} O + O_{2}

If you need to learn more about Decomposition reaction, click here

brainly.com/question/16987748?

#SPJ4

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Gravitational forces exerted on any two____in the universe
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2 years ago
What are duplet and octet elements ?Differentiate.​
Finger [1]
Octet means presence of a total of 8 electrons in its valence shell while in case of duplet only 2 electrons are present in valence shell.
4 0
3 years ago
Wavelengths are often represented in nm. What is the diameter of a helium (He) atom in
lianna [129]

Answer:

Diameter He = 0,1 nm.

Explanation:

Km to nm:

⇒ Diameter He = 1.0 E-13 Km * ( 1000 m / Km ) * (  1 E9 nm / m )

⇒ Diameter He = 0.1 nm

5 0
2 years ago
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vovangra [49]

Answer:

3

Explanation:

If oxygen reacts with iron, then both must be reactants and rust the product of that reaction

4 0
3 years ago
Read 2 more answers
4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K
swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

Pv =nRT

Assuming pressure as constant,

V∝ T

Now, let  K is the constant.

V = KT

Let initial volume of balloon , V_{1} = 4.3 liter

1000 liter = 1 meter cube

1 liter = \frac{1}{1000} m^{3} = 10^{-3} m^{3

4.3 liter = 4.3\times10^{-3}=4.3\times10^{-3} m^{3}

And initial temperature of balloon, T_{1} = 350 K

Let the final volume of balloon is V_{2}

And as given, final temperature of balloon, T_{2} is 250 K

Now, V_{1} = KT_{1}

4.3\times10^{-3}=K\times350\ (equation\ 1 )

V_{2} = KT_{2}

=K\times250\ (equation 2)

Dividing equation 1 and 2,

\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}

K cancelled by K.

By cross multiplication:

350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\          = \frac{1075\times10^{-3}}{350} \\          =2.87\times10^{-3}m^{3}

Now, convert it into liter with the help of calculation done above,

2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter

Therefore, volume of the gas in the balloon at 250 K will be  2.87 liter.

4 0
3 years ago
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