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blagie [28]
3 years ago
10

Why is acceleration negative in a free fall?

Physics
2 answers:
crimeas [40]3 years ago
6 0
Technically speaking altitude is measured from the ground up.
Therefore, say you're falling from 1000 metres, that number decreases till it reaches 0. Therefore, you're accelerating but towards the ground i.e. towards 0.

Therefore acceleration is negative because you're travelling at -x metres per second and accelerating at -x metres per second^2
murzikaleks [220]3 years ago
5 0
Only because when most people work with vertical motion, they call the upward direction positive. So falling objects have negative velocity and acceleration. But if you prefer to call the downward direction positive, you have every right to do that. Then the force of gravity on a falling object, as well as its velocity and acceleration, are all positive, and its negative altitude steadily grows until it hits the ground.
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What direction does centripetal acceleration point?
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Answer:

Inward

Explanation:

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What is the half-life of a radioisotope
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A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid
Sergeeva-Olga [200]

Answer:

8.37*10^5 rpm

Explanation:

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Rotational K.E is illustrated as (K.E)_{rt} = \frac{1}{2} I \omega^2

\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }

\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }

\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }

\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }

\omega = 87636.04

\omega = 8.76*10^4 rad/s

Since 1 rpm = \frac{2 \pi}{60}  rad/s

\omega = 8.76*10^4(\frac{60}{2 \pi})

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3 years ago
In this movable pulley, the input force is 20 N. What is the output force?
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