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uysha [10]
3 years ago
11

A puck of mass m 0.085 kg is going in a circle on a horizontal frictionless surface. It is held in its orbit by massless string

of length L = 0.84 m. The puck makes one revolution every t= 0.55 s. 50%
What the magnitude of the tension in the string, F, in Newtons, while it spins?
Physics
1 answer:
attashe74 [19]3 years ago
8 0

Answer:

Explanation:

Magnitude of tension

= centripetal force

= m ω²R

= m (2π/T)² R , T is time period of revolution.

= .085 x (2 x 3.14 / .55)² x .84

= 9.3  N .  

You might be interested in
Find the kenetic energy of a car of mass 700kg racing with a velocity of 10m/s
fiasKO [112]

Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

E_{k} = \frac{1}{2} mv^{2}

E_{k} = \frac{1}{2} (700)(10)^{2}

E_{k} = \frac{1}{2} (700)(100)

E_{k} = (350)(100)  OR E_{k} = \frac{1}{2} (70000)

E_{k} = 35000

Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

5 0
2 years ago
The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:38, so that the voltage of 120 v
matrenka [14]
Transformer contains two coils: primary and secondary. They allow change of voltage to lower or higher value. In first case we have step-down and in second case we have step-up transformer.
Formula used for transformer is:\frac{N_{1} }{N_{2}} = \frac{V_{1}}{V_{2}}

Where:N1 = number of turns on primary coilN2 = number of turns on secondary coilV1 = voltage on primary coilV2 = voltage on secondary coil
In a step-down transformer primary coil has more turns than secondary coil. So the ratio 1:38 means that for each turn on secondary coil we have 38 turns on primary coil.
We can solve the equation for V2:V_{2} =  \frac{ V_{1}* N_{2}  }{ N_{1} }  \\  V_{2} =  \frac{ 120* x  }{ 38x} } \\ V_{2} = 3.16V

Secondary coil provides voltage of 3.16V.
7 0
3 years ago
A ball thrown straight up into the air is found to be moving at 6.79 m/s after falling 1.87 m below its release point. Find the
MaRussiya [10]

Answer:

3.07 m/s

Explanation:

We know that from kinematics equation

v^{2}=u^{2}+2as and here, a=g where v is the final velocity, u is the initial velocity, a is acceleration, s is the distance moved, g is acceleration due to gravity

Making u the subject then

u=\sqrt {v^{2}-2gs}

Substituting v for 6.79 m/s, s for 1.87 m and g as 9.81 m/s2 then

u=\sqrt {6.79^{2}-(2\times 9.81\times 1.87)}=3.068338313 m/s\approx 3.07 m/s

5 0
3 years ago
if you have an isotope of the element carbon (C) that has the mass number of 14, what other information would help you determine
n200080 [17]
The number of protons
number of neutrons=the mass number- number of protons
14-6=8
4 0
3 years ago
When you trace the outline of your palm how do you find its area​
Tcecarenko [31]

Answer:

you count the squares or messure it

Explanation:

you can raw equal squares about 1 cm wide if possible all equal and count the squares eg theres 10 squares (small hand) so that would be 10cm squared

7 0
3 years ago
Read 2 more answers
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