Answer:
So, the target proton's speed is 777.82 m/s
And, the projectile proton's speed is 777.82 m/s
Explanation:
as per the system, it conserves the linear momentum,
so along x axis :
Mp V1 (i) = Mp V1 (f) cos θ1 + Mp V2 (f) cos θ2
along y axis :
0 = -Mp V1 (f) sin θ1 + Mp V2 (f) sin θ2
let us assume before collision it was moving on positive x axis, hence target angle will be θ2 = 45° from x axis
V2(f) = V1 (i) sin θ1 / ( cosθ2 sin θ1 + cos θ1 sin θ2)
= 1100 * sin 45 / ( cos 45 sin 45 + cos 45 sin 45 )
= 1100 * 0.7071 /( 0.7071 * 0.7071 +0 .7071 * 0.7071 )
= 777.82 /( 0.5 + 0.5)
= 777.82 m/s
(b)
the speed of projectile , V1 (f) = sinθ2 * V2(f) / sinθ1
= sin 45 * 777.82 / sin 45
= 777.82 m/s
So, the target proton's speed is 777.82 m/s
And, the projectile proton's speed is 777.82 m/s
