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2 years ago

Which of the following compounds' solubility will not be affected by a low pH in solution?

Chemistry

2 answers:

Finger [1]2 years ago

6 0

Which of the following compounds solubility CO(OH)2

Whitepunk [10]2 years ago

3 0

The compound solubility which will not be affected by a low pH in solution is AgBr.

pH is a measure of the acidity or basicity of any solution and according to the pH scale 0 to 6.9 shows the acidity, 7 is neutral and 7.1 to 14 shows the basicity of any solution.

AgBr is sparingly soluble in water and not soluble in acids, so if we low the pH of the solution towards the acidity its solubility not affected.
NiCO₃ is a basic salt and and shows solubility in the acidic medium so change in pH will affect its solubility.
Co(OH)₂ it is also a basic compound and shows its solubility in the acidic medium and get affected when change in pH takes place.
PbF₂ is a strong base and also shows solubility in the acidic medium easily, so get affected when change in pH takes place.
In CuS, sulphide is basic ion and whole compound shows solubility in the acidic medium and get affected when low pH of solution takes place.

AgBr is not affected by a low pH in solution.

To know more about solubility, visit the below link:

brainly.com/question/23946616

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What is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at

Alchen [17]

Answer:

4,313.43 mmHg is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at 850 mm Hg

Explanation:

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." This means that if the quantity of gas and the temperature remain constant, the product of the pressure for the volume always has the same value.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

If you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment and you vary the volume of gas to a new value V2, then the pressure will change to P2, it will be true:

P1 * V1 = P2 * V2

In this case:

V1=0.335 L
P1= ?
V2= 1700 mL= 1.7 L (Being 1 L=1000 mL)
P2= 850 mmHg

Replacing:

P1*0.335 L=850 mmHg*1.7 L

Solving:

$P1=\frac{850 mmHg*1.7 L}{0.335 L}$

P1=4,313.43 mmHg

4,313.43 mmHg is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at 850 mm Hg

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3 years ago

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