Answer:
Explanation:
1 ) Total mechanical energy of the car at the height of 10 m
1/2 mv² + mgh
.5 x 1800 x 25² + 1800 x 9.8 x 10 m
= 562500 + 176400
738900 J
If v be the velocity at the bottom ,
Total energy of the car at the bottom
1/2 m v² + 0
Applying conservation of energy
1/2 mv² = 738900
.5 x 1800 v² = 738900
v = 28.65 m /s
Energy required by car to ascend height of 15 m
1800 x 9.8 x 15
= 264600 J
b )
This energy is more that total energy of the car at the top that is 738900 J
so car can easily reach gas station .
If V be the velocity at the gas point
Total energy at the gas point
1/2 m V² + 264600
Applying conservation of energy
1/2 m V² + 264600 =738900
.5 x 1800 x V² = 474300
V = 22.95 m / s
d ) If R be the normal reaction at the bottom
net force
R - mg = m v² / r
R = m ( g + v² / r )
1800 ( 9.8 + 28.65² / 5 )
R = 313136 N
Answer:
a = 1 m/s²
Explanation:
given,
mass of the person = 60 Kg
Net External force exerted = 90 N
force of friction opposing the motion = 30 N
acceleration of the box = ?
Net force = External force applied - frictional force
Net force = 90 - 30
net force = 60 N
we know
F = mass x acceleration
60 = 60 x a
a = 1 m/s²
acceleration of the box is equal to a = 1 m/s²
Answer:
a = 10.07m/s^2
Their acceleration in meters per second squared is 10.07m/s^2
Explanation:
Acceleration is the change in velocity per unit time
a = ∆v/t
Given;
∆v = 50.0miles/hour - 0
∆v = 50.0miles/hours × 1609.344 metres/mile × 1/3600 seconds/hour
∆v = 22.352m/s
t = 2.22 s
So,
Acceleration a = ∆v/t = 22.352m/s ÷ 2.22s
a = 10.07m/s^2
Their acceleration in meters per second squared is 10.07m/s^2
Answer:
Diffusion is the movement of a molecule from an area where the molecule is in high concentration to an area where the molecule is in low concentration. Facilitated diffusion is the movement of a molecule from an area of high concentration to an area where the molecule is in low concentration. Osmosis is the diffusion (high to low concentration) of water through a semi-permeable membrane. Water moves from an area of high water molecule concentration (and lower solute concentration) to an area of low concentration (and higher solute concentration.
Hope this Helps!!!
Answer:
The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Explanation:
Given;
speed of the faster car, v₁ = 60 mi/h
speed of the slower car, v₂ = 55 mi/h
Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles
Note: divide 15 mins by 60 to convert to hours for consistency in the units.
Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
