Answer: r = 1.33 × 10^-5 mm
Explanation: The force per unit length of 2 current carrying conductor is given by the formulae below.
F/L = (u×I1×I2) /(2πr)
Where F/L = force per unit length = 7.73×10^-5mm = 0.0775 mm.
I1 = current on the first conductor = 4.27A
I2 = current on the second conductor = 1.19A
r = distance between both conductors.
u = permeability of free space = 1.25×10^-6
By substituting parameters, we have that
0.0775 = 1.25×10^-6 × 4.27 × 1.19/ 2πr
By cross multiplication
0.0775 ×2πr = 1.25×10^-6 × 4.27 × 1.19
r = 1.25×10^-6 × 4.27 × 1.19/ 0.0775 ×2π
r = 0.00000635162 / 0.0775 ×2π
r = 1.33 × 10^-5 mm
Answer:
0.1 m/s
Explanation:
Please see attached photo for explanation.
Mass of 1st cart (m₁) = 500 g
Initial velocity of 1st cart (u₁) = 0.25 m/s
Mass of 2nd cart (m₂) = 750 g
Initial velocity of 2nd cart (u₂) = 0 m/s
Velocity (v) after collision =.?
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(500 × 0.25) + (750 × 0) = v(500 + 750)
125 + 0 = v(1250)
125 = 1250v
Divide both side by 1250
v = 125 / 1250
v = 0.1 m/s
Thus, the two cart will move with a velocity of 0.1 m/s after collision.
Answer:
The friend on moon is richer.
Explanation:
The value of acceleration due to gravity changes from planet to planet. So the weight of 1 Newton of gold carries different mass on different places. So we need to calculate the mass of gold that both persons have.
<u>FRIEND ON MOON</u>:
W₁ = m₁g₁
where,
W₁ = Weight of Gold won by friend on moon = 1 N
m₁ = mass of gold won by friend on moon = ?
g₁ = acceleration due to gravity on moon = 1.625 m/s²
Therefore,
1 N = m₁(1.625 m/s²)
m₁ = 0.62 kg
<u>ON EARTH</u>:
W₂ = m₂g₂
where,
W₂ = Weight of Gold won by me on Earth = 1 N
m₂ = mass of gold won by me on Earth = ?
g₂ = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
1 N = m₁(9.8 m/s²)
m₁ = 0.1 kg
Since, the friend on moon has greater mass of gold than me.
<u>Therefore, the friend on moon is richer.</u>
Answer:
The atomic number is the number of protons in an atom's nucleus.
The atomic number is important, because it determines which element an atom is.
The length of the wire used is 3.162 m
<h3>Resistivity of a material</h3>
The formula for calculating the power is expressed as;
P = V²/R
Determine th resistance
R = V²/P
Determine the resistance of the heating coil by substituting
R = (110²/500)
R = 12100/500
R = 24.2ohms
Determine the length of the wire
R = ρL/A such that;
L = RA/ρ
Substitute the given parameters
diameter = 0.5 mm = 0.0005m
radius = 0.0005/2 = 0.00025 m
Determine the area
A = πr²
A = π * 0.00025²
A = 1.96*10^-7 m²
Determine the length
L = (24.2 * 1.96*10^-7 / 1.50*10^-6) =
L = 3.162 m
Hence the length of the wire used is 3.162 m
The length of the wire used is 3.162 m
Learn more on resistivity here; brainly.com/question/24858512
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