The Sun <span>produces energy by forming "Helium" in its core by the process of "Nuclear fusion"
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Answer:
The wavelength of the light is 562.5 nm
Solution:
As per the question:
Order, n = 1
Slit separation, d = 
Distance from the bright fringe, y = 0.18 m
Distance between the screen and the grating, D = 0.8 m
Now,
We know from the eqn for diffraction:

n = 1
(1)
Also,
For very small angle,
:
≈ 
Using the above value in eqn (1):

Answer:
Far point of the eye is 22.24 m
Far point of the eye is 0.4 m
Explanation:

Object distance = u
Image distance = v
Lens equation

Far point

Far point of the eye is 22.24 m
Object distance = u = 0.25-0.02 = 0.23 m


Near point

Far point of the eye is 0.4 m