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Zina [86]
3 years ago
9

The voltage in a battery is 9 volts. The resistance is 3 ohms. What is the current?

Physics
2 answers:
earnstyle [38]3 years ago
6 0
Current = V/R = 9/3 = 3A
fgiga [73]3 years ago
6 0

Answer: Voltage x Resistance = Current

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Lonnie pitches a baseball of mass 0.500 kg. The ball arrives at home plate with a speed of 35.0 m/s and is batted straight back
Andreyy89

Answer:

Explanation:

The impulse equation is

Δp = FΔt, where Δp = final momentum - initial momentum, F is the Force exerted on an object, and Δt is the change in time. In this equation,the entire right side defines the impulse. In other words, FΔt is the impulse; thus the change in momentum an object experiences is due to its change in impulse and is directly proportional to it.

Therefore, once we find the change in momentum, that is the impulse the object experiences. Δp = final momentum - initial momentum, where

p = mv and p is momentum.

p_f=(.500)(50.0) so

p_f=25.0 and

p_i=(.500)(35.0) so

p_i=17.5; therefore,

Δp = 25.0 - 17.5 = 7.5\frac{kg*m}{s} which is the unit for momentum

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2 years ago
Considere que helicóptero para na altitude a que voava para largar uma caixa de 90 kg para o solo.
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Answer:

El peso es de 882 newton.

Explicación:

El helicóptero se detiene a la altura en la que volaba para dejar caer una caja de 90 kg al suelo, el peso de la caja llega hasta los 882 Newton porque el peso es una fuerza dirigida hacia el centro de la tierra y depende de la gravedad. La fórmula del peso es multiplicar la masa por la gravedad, de modo que cuando se multiplican 90 kg de masa por 9,8 metros / seg2, obtenemos el peso del objeto que es 882 newton.

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Chegg ) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m(t)
stepladder [879]

Answer:

m(t)=20e^{-0.5t}

Explanation:

Given:

Initial mass of isotope (m₀) = 20 g

Half life of the isotope (t_{1/2}) = (ln 4) years

The general form for the radioactive decay of a radioactive isotope is given as:

m(t)=m_0e^{-kt}

Where,

m(t)\to mass\ after\ 't'\ years\\t\to years\ passed\\k\to rate\ of\ decay\ per\ year

So, the equation is: m(t)=20e^{-kt}

At half-life, the mass is reduced to half of the initial value.

So, at t=t_{1/2},m(t)=\frac{m_0}{2}. Plug in these values and solve for 'k'. This gives,

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Hence, the equation for the mass remaining is given as:

m(t)=20e^{-0.5t}

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