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aalyn [17]
3 years ago
15

I WILL GIVE BRAILYEST!!! What is the mass of an object moving at a velocity of 5 m/s if the momentum of the object is 50 kg•m/s?

Physics
2 answers:
lianna [129]3 years ago
7 0

Answer:

a. 250kg I think it's the right answer. hope it helps:)

Jlenok [28]3 years ago
7 0

Answer:

C.10

Explanation:

because when you divide 50 divided by 5 = 10

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Which object has more thermal energy a bowl of soup or pot of soup
jok3333 [9.3K]
A pot of soup because metal is a better conductor of heat and it stores more heat as well. thermal energy is heat energy. 

5 0
3 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
Work is a product of ___________.
alexgriva [62]
The correct option is D
4 0
3 years ago
Read 2 more answers
It requires 49 J of work to stretch an ideal very light spring from a length of 1.4 m to a length of 2.9 m. What is the value of
nadya68 [22]

Answer:

44 N/m

Explanation:

The extension, e, of the spring = 2.9 m - 1.4 m = 1.5 m

The work needed to stretch a spring by <em>e</em> is given by

W = \frac{1}{2} ke^2

where <em>k</em> is spring constant.

k = \dfrac{2W}{e^2}

Using the appropriate values,

k = \dfrac{2\times 49\text{ J}}{1.5^2\text{ m}^2} = 43.55\ldots\text{ N/m} \approx 44\text{ N/m}

3 0
3 years ago
Read 2 more answers
two resistors 6 ohm and 3 ohm are connected in parallel and its connected with a cell of EMF 6 volt find the current through eac
qaws [65]

Answer:

See below

Explanation:

Each resistor has 6 v applied across it

rememeber

V = IR     then     V/R = I

f<u>or the 6 Ω      6 v /6Ω  = 1 amp</u>

<u>for the 3 Ω       6v /3Ω = 2 amp</u>

8 0
1 year ago
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