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4 years ago

If all the light waves are reflected in equal amounts off an object then the object will appear

Physics

2 answers:

GalinKa [24]4 years ago

6 0

Then the object will appear the same color as the light shining on to it.

Fantom [35]4 years ago

3 0

The object would appear bright

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Find the acceleration of the system and the tension in the ropes for the system shown. The table mass is 30 kg and the hanging m

marusya05 [52]

The system's tension is 616 N and acceleration is 5.6 $m / s^{2}$

Explanation:

From newton’s second law of motion which state that net force acting on a body is product of mass of a body and acceleration of a body which is given as,

$F_{n e t}=m_{t o t} \times a$

Where,

$F_{n e t}$ is net force acting on body

$m_{\mathrm{tot}}$ is mass of body

a is acceleration of body

Given values

Table mass (m) = 30 kg

Hanging mass (m) = 40 kg

$a=\frac{F_{n e t}}{m_{\mathrm{tot}}}=\frac{m \times g}{m_{\mathrm{tot}}}$

Put the value for m = hanging mass = 40 kg and $g=9.8 \mathrm{m} / \mathrm{s}^{2}$ , we get

$a=\frac{40 \times 9.8}{30+40}=\frac{392}{70}=5.6 \mathrm{m} / \mathrm{s}^{2}$

The tension in the ropes, $T=(m \times g)+(m \times a)$

Here, m as hanging mass

T = tension, N or $k g m / s^{2}$

m = mass, kg

g = gravitational force, $9.8 \mathrm{m} / \mathrm{s}^{2}$

a = acceleration, $m / s^{2}$

$T = (40 \times 9.8)+(40 \times 5.6) = 392+224 = 616 N$

3 0

3 years ago

If a force of 10 N acts on an object and an additional force of 6 N acts on the object in the same direction. What will be the n

Schach [20]

Answer: The 1st one is B. I'm pretty sure the 2nd one is A. and the 3rd one is D.

Explanation: I hope this helped, although I'm not sure for the second one

4 0

3 years ago

Read 2 more answers

A flea walking along a ruler moves from the 45 cm mark to the 27 cm mark. It does this in 3 seconds. What is the speed? What is

ad-work [718]

Answer:

Explanation:

In the calculation of distance we do not take into account the direction of movement .So only magnitude of movement is taken care of.

On the other hand , in respect of displacement , we take into account even direction of movement along with magnitude.

Distance covered by flea = 45 - 27 = 18 cm

Displacement by flea = 27 - 45 = - 18 cm

Speed = Distance covered / time

= 18 / 3 = 6 cm / s

Velocity = - 18 / 3 = - 6 cm /s.

3 0

3 years ago

Two vectors are being added, one at an angle of 20.0 , and the other at 80.0. The only thing you know about the magnitudes is th

postnew [5]

Answer:a

Explanation: they are all positive

4 0

3 years ago

In an elastic collision, a 400-kg bumper car collides directly from behind with a second, identical bumper car that is traveling

kirza4 [7]

Answer:

v₁ = 3.5 m/s

v₂ = 6.4 m/s

Explanation:

We have the following data:

m₁ = mass of trailing car = 400 kg

m₂ = mass of leading car = 400 kg

u₁ = initial speed of trailing car = 6.4 m/s

u₂ = initial speed of leading car = 3.5 m/s

v₁ = final speed of trailing car = ?

v₂ = final speed of leading car = ?

The final speed of the leading car is given by the following formula:

$v_2=\frac{2m_1}{m_1+m_2}u_1-\frac{m_1-m_2}{m_1+m_2}u_2\\\\v_2=\frac{(2)(400\ kg)}{400\ kg+400\ kg}(6.4\ m/s)-\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(3.5\ m/s)$

v₂ = 6.4 m/s

The final speed of the leading car is given by the following formula:

$v_1=\frac{m_1-m_2}{m_1+m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\\\v_1=\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(6.4\ m/s)+\frac{(2)(400\ kg)}{400\ kg+400\ kg}(3.5\ m/s)$

v₁ = 3.5 m/s

4 0

3 years ago