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lakkis [162]
3 years ago
6

What is the chemical name for a compound with the formula ba3n2?

Chemistry
1 answer:
LekaFEV [45]3 years ago
3 0
Barium nitride 

copy the name of the metal as it is written in the periodic table and the first part of the name of the nonmetal (nitrogen)  and replace the end by "ide"
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What elements are present in this formula? : C7H8N4O2, How many atoms of each element are in this molecule? what patterns do you
iragen [17]

carbon, hydrogen, nitrogen, and oxygen. the number infront is how many of each element there are, they are increasing and decreasing

3 0
3 years ago
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2Fe + 3Cl2 → 2FeCl3 which of the following options gives the correct reactant ratio?
Mademuasel [1]

<u>Answer:</u> The reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

<u>Explanation:</u>

Mole ratio is defined as the ratio of the amount of moles of two substances that are participating in a chemical reaction.

In the given chemical equation:

2Fe+3Cl_2\rightarrow 2FeCl_3

The reactants are Fe and Cl_2 and the product is FeCl_3

The mole ratio is basically the stoichiometric ratio of the chemical compounds taking part in a chemical reaction.

The mole ratio of reactants is stoichiometric ratio of Fe and Cl_2, which is:

Fe:Cl_2=2:3

Hence, the reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

6 0
3 years ago
A 25.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/mol°C) is heated to 86.4°C and dropped into a calorimeter
Ira Lisetskai [31]

Answer:

m H2O = 56 g

Explanation:

  • Q = mCΔT

∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:

⇒ - (mCΔT)Al = (mCΔT)H2O

∴ m Al = 25.0 g

∴ Mw Al = 26.981 g/mol

⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al

⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C

⇒ Q Al = 1327.64 J

∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C

⇒ mH2O = 55.722 g ≅ 56 g

5 0
3 years ago
3. A magnet attracts a piece of metal. How is this event like a chemical bond?
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7 0
2 years ago
For the balanced equation shown below, how many moles of o2 will react with 0.3020 moles of co2? 2c2h5oh + 6o2 → 4co2 + 6h2o que
MariettaO [177]
The balanced reaction for combustion is as follows ;
2C₂H₅OH + 6O₂ ---> 4CO₂ + 6H₂O
the stoichiometry of C₂H₅OH to O₂ is 2:6
that means 2 mol of C₂H₅OH reacts with 6 mol of O₂.
when 1 mol of C₂H₅OH reacts with 6/2 mol of O₂,
then 0.3020 mol of C₂H₅OH reacts with - 6/2 x 0.3020
therefore number of O₂ moles reacted = 0.91 mol
6 0
3 years ago
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