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agasfer [191]
3 years ago
5

A watch loses 0.15 sec/min, how many seconds are lost in 24 hours?

Chemistry
2 answers:
Katen [24]3 years ago
6 0

Answer:  

0.15 sec/min = 9 sec/hour

9*24 = 216 seconds = 3.6 minutes

Explanation:

Alenkasestr [34]3 years ago
3 0

Answer:

216 Seconds

Explanation:

If every minute is 60 seconds than 60 multiplied by .15 is 9 Seconds Lost.

If every hour is 60 minutes compared to what we know than 24 hours multiplied by 60 is 1440 minutes.

Do the same math as before: 1440 x .15 = 216 Seconds

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In general, which of the following statements about electron-pair geometries is true?
Sergio [31]

Answer:

same

Explanation:

3 0
3 years ago
Which sample of matter is classified as a solution? 1. H2O(s) 2. H2O(l) 3. CO2(g) 4. CO2(aq)
lys-0071 [83]

Answer : Option 4) CO_{2}_{(aq)}

Explanation : CO_{2}_{(aq)} is the only sample of matter which can be classified as a solution. As the solution can be defined as a liquid mixture which contains a minor component (the solute) that is uniformly distributed within the major component (the solvent).

In this case, the solute is CO_{2} which is dissolved in water which acts as an solvent. Also, it has a subscript which is aq. which means aqueous, is often given to the solution in which the solvent is water.

Therefore, CO_{2}_{(aq)} is the correct answer.

4 0
4 years ago
Read 2 more answers
If the K a Ka of a monoprotic weak acid is 7.3 × 10 − 6 , 7.3×10−6, what is the pH pH of a 0.40 M 0.40 M solution of this acid?
olga_2 [115]

Answer:

pH =3.8

Explanation:

Lets call the monoprotic weak acid HA, the dissociation equilibria in water will be:

HA + H₂O   ⇄ H₃O⁺ + A⁻    with  Ka = [ H₃O⁺] x [A⁻]/ [HA]

The pH is the negative log of the H₃O⁺ concentration, we know the equilibrium constant, Ka and the original acid concentration. So we will need to find the [H₃O⁺] to solve this question.

In order to do that lets set up the ICE table helper which accounts for the species at equilibrium:

                          HA                                   H₃O⁺                          A⁻          

Initial, M             0.40                                   0                              0

Change , M          -x                                     +x                            +x

Equilibrium, M    0.40 - x                              x                               x

Lets express these concentrations in terms of the equilibrium constant:

Ka = x² / (0.40 - x )

Now the equilibrium constant is so small ( very little dissociation of HA ) that is safe to approximate 0.40 - x to 0.40,

7.3 x 10⁻⁶ = x² / 0.40  ⇒ x = √( 7.3 x 10⁻⁶ x 0.40 ) = 1.71 x 10⁻³

[H₃O⁺] = 1.71 x 10⁻³

Indeed 1.71 x 10⁻³ is small compared to 0.40 (0.4 %). To be a good approximation our value should be less or equal to 5 %.

pH = - log ( 1.71 x 10⁻³ ) = 3.8

Note: when the aprroximation is greater than 5 % we will need to solve the resulting quadratic equation.

4 0
3 years ago
What was the eutectic temperature (temperature from the two lines of best fit cross) for the mixture
Ymorist [56]

Answer:

hello your question is incomplete below is the missing part of the question

answer : 104°c

Explanation:

The Eutectic temperature  for the mixture is 104°c

From the chart attached below it can be seen that the temperature from the two lines of best fit cross is 104°c

7 0
3 years ago
013 10.0 points
34kurt

Answer:

this isn't immediately clear, it can be seen in ... CO2? 1. 6.0 × 10−23 g. 2. 44 g. 3. 7.31 × 10−23 g correct. 4. 6.0 × 10. 23 g. 5. 7.31 × 10 ... 40.0 grams of S will react leaving 10.0 grams. S unreacted. 013. 10.0 points ... FeCl2 and K2CO3 is ... 9. 1. There is no reaction. 2. KCl electrolyte. 3. CO2 gas. 4. FeCO3 precipitate. correct.

Explanation:

5 0
3 years ago
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