Answer: 1800 L
Explanation:
Given that,
Original pressure of gas (P1) = 180 kPa
Original volume of gas (V1) = 1500 L
New pressure of gas (P2) = 150 kPa
New volume of gas (V2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P1V2
180 kPa x 1500 L = 150 kPa x V2
270000 kPa•L = 150 kPa•V2
Divide both sides by 150 kPa
270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa
1800L = V2
Thus, the new volume of the gas is 1800 liters.
C. protons and neutrons combined
B. Speed up chemical reactions
The equation is given is of combustion of ethanol.
Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.
The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.
Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.
The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.
To conclude with we can say that the given reaction of combustion of ethanol. Ethanol with oxygen given carbon dioxide with water on reaction.
Learn more about Combustion of ethanol here:
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