Answer:
Usually a handbook or website
Answer:
(N-1) × (L/2R) = (N-1)/2
Explanation:
let L is length of packet
R is rate
N is number of packets
then
first packet arrived with 0 delay
Second packet arrived at = L/R
Third packet arrived at = 2L/R
Nth packet arrived at = (n-1)L/R
Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R
Now
L / R = (1000) / (10^6 ) s = 1 ms
L/2R = 0.5 ms
average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2
the average queuing delay of a packet = 0 ( put N=1)
Answer:288 pm
Explanation:
Number of atoms(s) for face centered unit cell -
Lattice points: at corners and face centers of unit cell.
For face centered cubic (FCC), z=4.
- whereas
For an FCC lattices √2a =4r =2d
Therefore d = a/√2a = 408pm/√2a= 288pm
I think with this step by step procedure the, the answer was clearly stated.
Answer:
shrinkage ratio = 1.538
Explanation:
given data
water content = 22 %
dry density γ = 82 pcf
required dry density specified γ' = 96 pcf
required to produce = 50,000 yd³ = 50000 × 27 = 1350,000 ft³
solution
we get here first volume of borrow pit that is we know that
dry density ∝
so

v = 1580487.8 ft³
v = 58536.58 yd³
so here
shrinkage ratio will be as
shrinkage ratio =
shrinkage ratio = 1.538