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forsale [732]
3 years ago
5

Fuel Combustion and CO2 Sequestration [2016 Midterm Problem] Long-term storage of carbon dioxide in underground aquifers or old

oil fields is one method to prevent release of CO2 to the atmosphere (to help mitigate climate change). This is referred to as carbon sequestration. A power plant burns fuel oil containing 39.0 mol% C, 60.3 mol% H, and 0.70 mol% S at a rate of 290 kmol/hr. An air stream flowing at 945 kmol/hr provides oxygen for the combustion process. Conversion of the fuel is 95%. Of the C that burns, 90% goes to CO2. The gases are then separated and the carbon dioxide is sequestered underground. Assume 100% separation of the CO2 from the other gases. (a) Draw a flowchart (reactor and separation unit) and label all streams. Incorporate all of the information given above (b) Calculate the percent excess air fed. (c) Determine the molar flowrate of the O2 in the stack gas leaving the plant (d) What is the mass flowrate of CO2 into the underground aquifer?

Engineering
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

The answers are on the attachment.

Explanation:

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Consider the following Moore’s law growth pattern (since 1980) for the number of transistors inside a particular commercial micr
Fantom [35]

Answer:

No. of transistors = $4.1524 \times 10^{10}$ transistors

Explanation:

Given that:

N = $1920 \times 10^{0.163(Y-1980)}$

Y = 2025

N = $1920 \times 10^{0.163(2025-1980)}$

N = $4.1524 \times 10^{10}$ transistors

Now at Y = 1980

Number of transistors N = 1920

Therefore,

$1000 = 10^{0.163(Y-1980)}$

$\log_{10} 1000=0.163(Y-1980)$

$\frac{3}{0.163}=Y-1980$

18 ≅ 18.4 = Y - 1980

Y = 1980 + 18

   = 1998

So, to increase multiples of 1000 transistors. it takes 18 years.

5 0
3 years ago
A closed system contains propane at 35°c. It produces 35 kW of work while absorbing 35 kW of heat. What is process? the temperat
salantis [7]

Answer:

35°c

Explanation:

Given data in question

heat = 35 kw

work = 35 kw

temperature = 35°c

To find out

temperature of the system after this process

Solution

we know that first law of thermodynamics is Law of Conservation of Energy

i.e  energy can neither be created nor destroyed and it can be transferred from one form to another form

first law of thermodynamics is energy (∆E) is sum of heat (q) and work (w)

here we know

35 = 35 + m Cv ( T - t )

35-35 = m Cv ( T-t )

T = t

here T = final temperature

t = initial temperature

it show final temp is equal to initial temp

so we can say temp after process is 35°c

3 0
3 years ago
A surface grinding operation is used to finish a flat plate that is 5.50 in wide and 12.500 in long. The starting thickness is 1
valina [46]

Answer:

77.40

Explanation:

Initial width = 5.5 Inches

Initial length = 12.5 inches

Initial thickness = 1.085 inches

After grinding

Thickness of flat plate  = 1 inch

Grinding wheel

starting diameter( di )= 6.013 inches

width of grinding wheel = 0.5 inch

After operation

Diameter of grinding wheel ( df ) = 5.997

<u>Calculate the grinding ratio in this operation</u>

First step : determine the volume of material removed from flat plate

= Length of flat plate * width of flat plate * change in thickness

= 12.5 * 5.5 * ( 1.085 - 1 )

= 5.8437 in^3

Volume of material from grinding wheel

= π / 4 * ( di^2 - df^2 ) * width  

= π / 4  * ( 6.013^2 - 5.997^2 ) * 0.5

= 0.0755 in^3

<u>Finally the Grinding ratio</u>

= 5.8437  / 0.0755

= 77.4

5 0
3 years ago
Air at 300 K and 100 kPa steadily flows into a hair dryer having electrical work input of 1500 W. Because of the size of the air
dezoksy [38]

Answer:

0.0280Kg/s

Explanation:

Given:

W = 1500

V2 = 300

V1 = 0

Q = 0 ( adiabatic)

T1 = 300

T2 = 20 m/s = converting to degrees we have 353°c

Let's use the energy equation

Q - W = m_• *( Cp(dT) + 0.5*(V2^2 - V1^2) Q = 0

[/tex] m_• = W / (Cp(dT) + 0.5*V2^2) [/tex]

= 1500 / (1005(353 - 300) + 0.5*21^2)

= 1500 W / 53485.5 =0.0280 kg/s

8 0
4 years ago
Read 2 more answers
How does accenture generate value for clients through agile and devops?
Stells [14]
By permanently locking in stakeholder requirements during a project's planning phase
4 0
3 years ago
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