The benefits of observing good safety measures in relation to an increase in productivity within a pharmaceutical laboratory is that the act of adhering to all these policies helps a lot of employees to hinder the spills of chemicals and other kinds of accidents, as well as reduce the damage to the environment that is outside of the lab.
<h3>What are the benefits of practicing safety in the laboratory?</h3>
A laboratory is known to be one that is known to have a lot of potential risks that is said to often arise due to a person's exposure to chemicals that are corrosive and toxic, flammable solvents, high pressure gases and others.
Therefore, A little care and working in line to all the prescribed safety guidelines will help a person to be able to avoid laboratory mishaps.
Therefore, The benefits of observing good safety measures in relation to an increase in productivity within a pharmaceutical laboratory is that the act of adhering to all these policies helps a lot of employees to hinder the spills of chemicals and other kinds of accidents, as well as reduce the damage to the environment that is outside of the lab.
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Answer:
c. 25 μA
Explanation:
The dependent current source means that 31 times i1 will flow through the 6kΩ resistor, effectively increasing its voltage drop to 31 times that which would result from i1 alone. In effect, the 6kΩ resistor behaves in the left-side circuit loop as though it were 31×6kΩ = 186kΩ (with no dependent current source).
Then the current i1 is equivalent to that created by a 5+1 = 6V source through a 54kΩ +186kΩ = 240kΩ circuit impedance.
(6V)/(240kΩ) = 25 μA
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<em>Additional comment</em>
The voltage across the 6kΩ resistor is (186/240)·6V = 4.65V, and the 25 μA current generates a voltage of 30·(25 μA)(1.8kΩ) = 1.35V across the 1.8kΩ resistor. This means the voltage source at the right side of the diagram needs to be at least 4.65 +1.35 = 6.0V in order to support the calculated voltage drops.
Answer:
The statement (a) In a non-deterministic FSM, a string is invalid if there is one path not leading to a final state is NOT true
Explanation:
A non-deterministic FSM, contrary to deterministic FSM which has only one possible thread of execution, has multiple threads and for the machine to be invalid, all threads should lead to a none accepting (final) state.
Answer:
1). 340.41N/m^2
2). 0.743_m/s
3). 12.29_m/s
4). 0.168_m^3/s
Explanation:
Applying Bernoulli's equation
P₁ + 0.5ρv₁² + ρgh₁ = P₂ + 0.5ρv₂² + ρgh₂
the velocity in the 13 cm diameter pipe is given by
flow rate = 84 L/s
1). Height=7.7+26+1=34.7_m
Density= 1_Kg/m^3
Acceleration due to gravity = 9.81_m/s^2
Pressure = density×height×gravity
= 340.41N/m^2
2). Level of the tank drops by
Taking the tank as a pipe
v = pi × r^2 × h = flow rate through the pipe
= 84_L/s
r = 6.0_m, h = 7.7_m
Level drop by 84/(6×7.7)_m/s
= 0.743_m/s
3). Speed of water shoot out v = Sqr(2×g×h) = Sqr(2×9.81×7.7) = 12.29_m/s
4). Volume flow rate = v × a = 12.29×0.014 = 0.168_m^3/s
