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hammer [34]
3 years ago
6

1) Which of the following is not a dwarf planet?

Physics
2 answers:
Phoenix [80]3 years ago
6 0
<h2>Answer 1)</h2>

<u>In the given options </u><u>Io is not a dwarf planet</u>

<h2>Explanation: </h2>

Jupiter's moon Io is a volcanically active body in the Solar System, with hundreds of volcanoes, in which some erupting lava fountains dozens of miles high. Io is situated between Jupiter's massive gravity and the smaller but precisely timed pulls from two neighboring moons Europa and Ganymede that orbit farther from Jupiter.

<h2>Answer 2) </h2>

<u>The answer is </u><u>C) Spiral, elliptical, irregular</u>

<h2>Explanation: </h2>

There are three main types of galaxies. Elliptical, Spiral, and Irregular. Elliptical galaxies are shaped like a spheriod, or elongated sphere.  These galaxies have no particular axis of rotation.  Then spiral galaxies consist of a flat, rotating disk containing stars, gas and dust, and a central concentration of stars known as the bulge. The last one An irregular galaxy is a galaxy that does not have a distinct regular shape, unlike a spiral or an elliptical galaxy.  

<h2>Answer 3)  </h2>

<u>The correct answer is </u><u>D) Waves and particles</u>

<h2>Explanation:</h2>

An important fact about light is that light travels and behaves as waves when it passes through empty space or a vacuum. Light also has the character of a particle, but there are not more experiments about light as a particle in space because light has slightly slower speeds when it travels through denser material such as a planet's atmosphere or a piece of glass.

<h2>Answer 4) </h2>

<u>The correct answer is </u><u>White Dwarf</u>

<h2>Explanation: </h2>

A white dwarf is a small very dense star that is typically the size of a planet. A white dwarf is formed when a low-mass star has exhausted all its central nuclear fuel and lost its outer layers as a planetary nebula. A white dwarf is very dense: its mass is comparable to that of the Sun, while its volume is comparable to that of Earth. And they are located in the lower left of the H-R diagram because they are hot but not very bright

<h2> Answer 5</h2>

<u>The answer is </u><u>D) By using the celestial sphere and constellations</u>

<h2>Explanation: </h2>

There are many ways that scientists use to find the exact location of stars but the most common method to find  the position of objects in the sky is by using coordinates. The easiest way to do this is to use coordinate systems which assume that all objects in space are at the same distance, on the inside of an imaginary celestial sphere. The celestial sphere is an imaginary sphere of gigantic radius with the earth located at its center.  

vodomira [7]3 years ago
5 0
1 io is a moon not a planet.
2)C,The Milky Way is a spiral galaxy
3)D,this is called the particle wave duality,stuff can act like particles and waves at the same time.
4)the white dwarfs
5)using distance and compass direction(I’m not sure about this one though)
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Recall the equation for magnetic force:

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4 years ago
Explain how the basic unit are combined to give the derived units of force, velocity, pressure and work
LuckyWell [14K]

Velocity:

Velocity is change in displacement with respect to time:

\frac{\Delta x}{\Delta t}

Analysing the units, meters (displacement) and seconds (time) are basic units:

\frac{m}{s}

Therefore the unit of velocity is m/s

Force:

Newton's second law of motion:

F = ma

Kilogram (mass) is a basic unit, and accelerations unit can be found using the equation:

a=\frac{\Delta v}{\Delta t}

Analysing the units:

\frac{\frac{m}{s}}{s}=\frac{m}{s^2}

Therefore, the unit of force is:

kg\frac{m}{s^2}

Pressure:

Pressure is given by the equation:

P=\frac{F}{S} where S is area of effect, F is force

Area for a basic rectangle (geometric shape is arbitrary for dimensional analysis) is found by multiplying two lengths:

[l^2]=m^2, the unit of area

Dividing the aforementioned unit of force by the unit of area:

\frac{kg\frac{m}{s^2}}{m^2}=\frac{kg}{ms^2}, the unit of pressure

Work:

Work is given by the equation:

W=\vec{F}\cdot \vec{x}, (dot product may be assumed as normal multiplication for the purposes of unit analysis)

Knowing displacement's (x) unit is m:

[W]=\frac{kgm}{s^2}m=\frac{kgm^2}{s^2}, the unit of work.

3 0
3 years ago
Which statement accurately represents the arrangement of electrons in Bohr’s atomic model?
noname [10]

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Explanation:

The statement that accurately represents the arrangement of electrons in Bohr’s atomic model is that the electrons move around the nucleus in fixed orbits of equal levels of energy.

It should be noted that the electrons have a fixed energy level when they travel around the nucleus in with energies which varies for different levels.

Higher energy levels are depicted by the orbits that are far from the nucleus. There's emission of light when the electrons then return back to a lower energy level.

8 0
3 years ago
Define anterior and posterior in correlation to the body. (ANATOMY)
tatyana61 [14]

Answer:

it should be right it's from go.ogle hm!!!

Explanation:

Anterior or ventral - front (example, the kneecap is located on the anterior side of the leg). Posterior or dorsal - back (example, the shoulder blades are located on the posterior side of the body). Medial - toward the midline of the body (example, the middle toe is located at the medial side of the foot).

8 0
3 years ago
Read 2 more answers
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?
konstantin123 [22]

Answer:

I=2.71\times 10^{-5}\ A

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.  

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}, r is radius

Let I is the displacement current. It is given by :

I=C\dfrac{dV}{dt}

Here, \dfrac{dV}{dt} is rate of increasing potential difference

So

I=\dfrac{\pi r^2\epsilon_o}{d}\times \dfrac{dV}{dt}\\\\I=\dfrac{\pi (0.03)^2\times 8.85\times 10^{-12}}{0.46\times 10^{-3}}\times 500000\\\\I=2.71\times 10^{-5}\ A

So, the value of displacement current is 2.71\times 10^{-5}\ A.

4 0
3 years ago
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