All categories

3 years ago

1) Which of the following is not a dwarf planet?

Physics

2 answers:

Phoenix [80]3 years ago

6 0

<h2>Answer 1)</h2>

<u>In the given options </u><u>Io is not a dwarf planet</u>

<h2>Explanation: </h2>

Jupiter's moon Io is a volcanically active body in the Solar System, with hundreds of volcanoes, in which some erupting lava fountains dozens of miles high. Io is situated between Jupiter's massive gravity and the smaller but precisely timed pulls from two neighboring moons Europa and Ganymede that orbit farther from Jupiter.

<h2>Answer 2) </h2>

<u>The answer is </u><u>C) Spiral, elliptical, irregular</u>

<h2>Explanation: </h2>

There are three main types of galaxies. Elliptical, Spiral, and Irregular. Elliptical galaxies are shaped like a spheriod, or elongated sphere. These galaxies have no particular axis of rotation. Then spiral galaxies consist of a flat, rotating disk containing stars, gas and dust, and a central concentration of stars known as the bulge. The last one An irregular galaxy is a galaxy that does not have a distinct regular shape, unlike a spiral or an elliptical galaxy.

<h2>Answer 3) </h2>

<u>The correct answer is </u><u>D) Waves and particles</u>

<h2>Explanation:</h2>

An important fact about light is that light travels and behaves as waves when it passes through empty space or a vacuum. Light also has the character of a particle, but there are not more experiments about light as a particle in space because light has slightly slower speeds when it travels through denser material such as a planet's atmosphere or a piece of glass.

<h2>Answer 4) </h2>

<u>The correct answer is </u><u>White Dwarf</u>

<h2>Explanation: </h2>

A white dwarf is a small very dense star that is typically the size of a planet. A white dwarf is formed when a low-mass star has exhausted all its central nuclear fuel and lost its outer layers as a planetary nebula. A white dwarf is very dense: its mass is comparable to that of the Sun, while its volume is comparable to that of Earth. And they are located in the lower left of the H-R diagram because they are hot but not very bright

<h2> Answer 5</h2>

<u>The answer is </u><u>D) By using the celestial sphere and constellations</u>

<h2>Explanation: </h2>

There are many ways that scientists use to find the exact location of stars but the most common method to find the position of objects in the sky is by using coordinates. The easiest way to do this is to use coordinate systems which assume that all objects in space are at the same distance, on the inside of an imaginary celestial sphere. The celestial sphere is an imaginary sphere of gigantic radius with the earth located at its center.

vodomira [7]3 years ago

5 0

1 io is a moon not a planet.
2)C,The Milky Way is a spiral galaxy
3)D,this is called the particle wave duality,stuff can act like particles and waves at the same time.
4)the white dwarfs
5)using distance and compass direction(I’m not sure about this one though)

You might be interested in

1) On the way to the moon, the Apollo astro-

kramer

(1) You must find the point of equilibrium between the two forces,

<span>G * <span><span><span>MT</span><span>ms / </span></span><span>(R−x)^2 </span></span>= G * <span><span><span>ML</span><span>ms / </span></span><span>x^2
MT / (R-x)^2 = ML / x^2

So,

x = R * sqrt(ML * MT) - ML / (MT - ML)
R = is the distance between Earth and Moon.

</span></span></span>The result should be,
x = 3.83 * 10^7m
from the center of the Moon, and

R - x = 3.46*10^8 m
from the center of the Earth.

(2) As the distance from the center of the Earth is the number we found before,
d = R - x = 3.46*10^8m
The acceleration at this point is
g = G * MT / d^2
g = 3.33*10^-3 m/s^2

6 0

3 years ago

What term was used to describe the final digit

xxMikexx [17]

Answer:

Significant digits (also called significant figures or “sig figs” for short) indicate the precision of a measurement. A number with more significant digits is more precise. For example, 8.00 cm is more precise than 8.0 cm.

7 0

2 years ago

A car accelerates from rest at 3.00 m/second squared What is the velocity after 5 secs ? What is the displacement after 5 second

andrey2020 [161]

Explanation:

after 5 seconds, the velocity is (5s)(3m/s²) = 15m/s

The displacement after 5s is

x=vo + (1/2)at²

x = 0 + (1/2)(3m/s²)(5s)(5s)

x= 37.5 m

3 0

3 years ago

To add to the complexity, those precious atoms face the peril of disintegrating into the void. Luckily, by now, they are feeling

miskamm [114]

Answer:

B The most basic atoms were formed due to the force of gravity.

Explanation:

Since the statement says that the atoms could have faced the peril of disintegrating into the void, this means that, they could have been destroyed by movement away into the void.

But, it also says that by now, they are feeling the influence of gravity to bring them safely together. This statement shows that gravity brings them (the atoms) together and thus doesn't allow them disintegrate into the void.

<u>So, a reader can thus infer that the most basic atoms were formed due to the force of gravity since it doesn't allow the atoms disintegrate into the void.</u>

So, B is the answer.

5 0

2 years ago

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is . Find the time i

a_sh-v [17]

Answer:

a)<em> It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves. </em>

b) <em>The minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds. </em>

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:

Gamma rays

X-rays

Ultraviolet rays

Visible region

Infrared

Microwave

Radio waves.

Any radiation that belongs to electromagnetic spectrum has a speed in vacuum of $3x10^{8}m/s$ .

<em>a) Find the time it took for his voice to reach the Earth via radio waves.</em>

To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:

$c = \frac{d}{t}$ (1)

Where v is the speed of light, d is the distance and t is the time.

Notice that t can be isolated from equation 1.

$t = \frac{d}{c}$ (2)

The distance from the Earth to the Moon is $3.85x10^{8} m$ , therefore.

$t = \frac{3.85x10^{8} m}{3x10^{8}m/s}$

$t = 1.28s$

Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

<em>b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.</em>

The distance from the Earth to the Mars at its closest approach is $5.76x10^{10}m$ , therefore.

$t = \frac{5.76x10^{10}m}{3x10^{8}m/s}$

$t = 192s$

Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

3 0

3 years ago