Using the constant acceleration formula v^2 = u^2 + 2as, we can figure out that it would take a distance of 193.21m to reach 27.8m/s
The periods of oscillation for the mass–spring systems from largest to smallest is:
- m = 4 kg , k = 2 N/m (T = 8.89 s)
- m = 2 kg , k = 2 N/m (T = 6.28 s)
- m = 2 kg , k = 4 N/m (T = 4.44 s)
- m = 1 kg , k = 4 N/m (T = 3.14 s)
<h3>Explanation:</h3>
The period of oscillation in a simple harmonic motion is defined as the following formulation:
Where:
T = period of oscillation
m = inertia mass of the oscillating body
k = spring constant
m = 2 kg , k = 2 N/m
T = 6.28 s
m = 2 kg , k = 4 N/m
T = 4.44 s
m = 4 kg , k = 2 N/m
T = 8.89 s
m = 1 kg , k = 4 N/m
T = 3.14 s
Therefore the rank the periods of oscillation for the mass–spring systems from largest to smallest is:
- m = 4 kg , k = 2 N/m (T = 8.89 s)
- m = 2 kg , k = 2 N/m (T = 6.28 s)
- m = 2 kg , k = 4 N/m (T = 4.44 s)
- m = 1 kg , k = 4 N/m (T = 3.14 s)
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Explanation:
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it is given by :
...............(1)
Where m₁ and m₂ are masses
r is the distance between them
It is clear from equation (1) that :
1. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.
2. The gravitational force between two objects is proportional to the product of the masses of the two objects.
Hence, this is the required solution.
Answer:
s = 90 m
a = 56 m/s²
Explanation:
I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t
Position is the integral of differential velocities
s =
s = 3t³ + t² | from 0 to 3
s = 3(3)³ + 3² - (0) = 90 m
acceleration is the derivative of velocity
a = v' = 18t + 2
a(3) = 18(3) + 2 = 56 m/s²
Answer: The San Andreas Fault
Explanation: Hope this helps ^^