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marusya05 [52]
3 years ago
9

What is the following product √10 * √10 10 10√10 100 2√10

Physics
2 answers:
insens350 [35]3 years ago
8 0
√10(√10) = √10^2

The root and the square cancels:
√10^2 = 10

10 is your answer

hope this helps
qwelly [4]3 years ago
7 0

Answer:

The result of the product √10*√10 is 10

Explanation:

To solve this product, it is first appropriate to apply the property of root multiplication with the same index.  This property indicates that multiplying two roots with the same index is the same as multiplying on a single root with that index. In this case this property is applied as follows:

\sqrt{10} *\sqrt{10} =\sqrt{10*10}

Now you can think of the next step in two ways. One of them is to multiply within the root and then solve the root as follow:

\sqrt{10*10} =\sqrt{100} =10

Another way is to express the values ​​within the root as power, because they are the same number.

\sqrt{10*10} =\sqrt{10^{2} }

The root is the opposite operation to the power, then the root nullification property can be applied: if you have an elevated number or variable to an exponent that is within a root with the same index, the power with the root is voids:

\sqrt{10^{2} } =10

Note that in both cases the result is the same, so the method you choose to resolve this account is indistinct. <em><u>The result of the product √10*√10 is 10</u></em>.

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3 years ago
A lumberjack (mass = 103 kg) is standing at rest on one end of a floating log (mass = 255 kg) that is also at rest. The lumberja
mina [271]

Answer:

(a) -1.18 m/s

(b) 0.84 m/s

Explanation:

(a)

The total linear momentum before the lumberjack begins to move is zero because all parts of the system are at res

From the law of conservation of momentum

m1v1+m2v2=0 hence m1v1=-m2v2 where m1 is mass of lumberjack, v1 is velocity of lumberjeck, m2 is mass of floating log, v2 is velocity of the floating log.

Substituting M1 for 103 Kg, V1 for 2.93 m/s, M2 for 255 Kg into the above equation we obtain

103Kg*2.93 m/s=-255Kg*V2

V2=-(103 kg*2.93 m/s)/255=-1.183490196  m/s

Hence V2=-1.18 m/s

(b)

For the second log

V(M1+M2)=m1v1 where V is the common velocity

V(103 Kg+255 Kg)=103 Kg*2.93 m/s

V=(103 Kg*2.93 m/s)/(103 Kg+255 Kg)=0.842988827  m/s

V=0.84 m/s

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3 years ago
The edge effect in habitats are caused by:
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Read 2 more answers
Steel is very stiff, and the Young's modulus for steel is unusually large, 2.0×1011 N/m2. A cube of steel 25 cm on a side suppor
TEA [102]

Answer:

Force (normal) = 833.85 N Compression = 1.67 x 10⁻⁸ m

Explanation:

Given data Young's Modulus (Y) = 2 x 10¹¹ N/m², Length of one side of cube = 25 cm = 0.25 m, mass of load = 85 kg

Normal force is the force exerted upon an object that is in contact with another stable object. This force would be applied by the surface onto the object in the same vector and is used to keep the object stable while it rests on a surface.

We know from Newton's Second Law that

F = ma where m is the mass and a is the acceleration (<em>in this case due to gravity</em>) hence, the normal opposing force to the load applied by the surface would be equal to the force applied on the surface by the weight of the load on the surface, So

F (normal) = M (load) x a = 85 x 9.81 = 833.85 N

Compression is the change in length of an object by the exertion of force upon it. Using the Young's Modulus formula we can find this change in the cube of steel. The Young's Modulus is given by

Y = (F/A)/(ΔL/L), where Y is the Young's Modulus, F is the Force being applied on the object, A is the cross sectional area on which the said force is applied, ΔL is the change in length due to said force being applied and L is the original Length of the side of the cross sectional area.

Solving this for ΔL, we can re- arrange the equation

ΔL = (F x L)/(Y x A) since area of square is L x L we can simplify the equation to get

ΔL = (F)/(Y x L), substitute the values

ΔL = (833.85)/(2 x 10¹¹ x 0.25) = 1.67 x 10⁻⁸m

6 0
3 years ago
The energy associated with the seperation of two electrical charges is called
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