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marusya05 [52]
3 years ago
9

What is the following product √10 * √10 10 10√10 100 2√10

Physics
2 answers:
insens350 [35]3 years ago
8 0
√10(√10) = √10^2

The root and the square cancels:
√10^2 = 10

10 is your answer

hope this helps
qwelly [4]3 years ago
7 0

Answer:

The result of the product √10*√10 is 10

Explanation:

To solve this product, it is first appropriate to apply the property of root multiplication with the same index.  This property indicates that multiplying two roots with the same index is the same as multiplying on a single root with that index. In this case this property is applied as follows:

\sqrt{10} *\sqrt{10} =\sqrt{10*10}

Now you can think of the next step in two ways. One of them is to multiply within the root and then solve the root as follow:

\sqrt{10*10} =\sqrt{100} =10

Another way is to express the values ​​within the root as power, because they are the same number.

\sqrt{10*10} =\sqrt{10^{2} }

The root is the opposite operation to the power, then the root nullification property can be applied: if you have an elevated number or variable to an exponent that is within a root with the same index, the power with the root is voids:

\sqrt{10^{2} } =10

Note that in both cases the result is the same, so the method you choose to resolve this account is indistinct. <em><u>The result of the product √10*√10 is 10</u></em>.

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A rectangular sharp-crested weir is contracted on both sides, and the opening is 1.2 m wide. At what height (Hw) should it be pl
Alex

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

Q = C_w BH^{3/2}

H = (\dfrac{Q}{C_wB})^{2/3}

H = (\dfrac{0.5}{1.84\times 1.2})^{2/3}

H = 0.371\ m

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

H_w = 2.129 m

Height at which weir should place is equal to 2.129 m.

7 0
3 years ago
irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Ano
Norma-Jean [14]

The actual distance of Regulus from Earth is 23.81 parsecs.

Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.

Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

            p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

  = 1 / (0.042)                                     [ 1 parsecs = 1 arcseconds ]

  = 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

Learn more about astronomical units here:

<u>brainly.com/question/16471213</u>

#SPJ4

6 0
1 year ago
Which of the following statements is TRUE about updating the exposure control plan?
iren2701 [21]

Statements that are true as regards exposure control plan and its updating are;

<em>Updates must have the  reflection of changes in tasks as well in procedures.</em>

<em>Updates must reflect changes in positions that affect occupational exposure.</em>

<em>Updates must have the cost of PPE that is needed and  necessary to reduce exposure</em>

An exposure control plan can be regarded as  the framework for compliance between the employer and the workers.

  • This framework give room for the employer to creates a written plan that will help in protecting their workers from bloodborne pathogens.

  • This plan gives hope to workers in term of protection when working with their Employer.

  • There are some elements that is associated with  Exposure Control Plan, and theses are;
  1. Health hazards as well as  risk that is attributed to  each product in the worksite.
  2. Statement of purpose.
  3. procedures and practices in a written form
  4. Responsibilities from the Manager, CEO, designated resources and employer.

Therefore, exposure control plan is avenue to protect workers from bloodborne pathogens.

brainly.com/question/1203927?referrer=searchResults

3 0
2 years ago
What effect does an unbalanced force have on an object?
Mars2501 [29]
<span>it either changes the direction of the object or it stops the object in motion.</span>
5 0
3 years ago
Read 2 more answers
Scientists and astronomers have found that in galaxies with central black holes, there are also large star formations near those
sweet-ann [11.9K]

Answer:

B

Explanation:

nothing to do with black holes creating star or related

5 0
3 years ago
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