A ball is launched horizontally at 4 m/s
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Answer:
9.6 rad/s
Explanation:
= length of the metal rod = 50 cm = 0.50 m
= Mass of the long metal rod = 780 g = 0.780 kg
Moment of inertia of the rod about one end is given as
= force applied by the hammer blow = 1000 N
Torque produced due to the hammer blow is given as
= time of blow = 2.5 ms = 0.0025 s
= Angular velocity after the blow
Using Impulse-change in angular momentum, we have