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krek1111 [17]
2 years ago
8

An object travels a distance d with acceleration a over a period of time t according to the equation: d = at² After 2.3 seconds

with an acceleration of 9.8 m/s2, how far does an object travel (rounding the answer to two significant figures)?​

Physics
1 answer:
matrenka [14]2 years ago
5 0

Answer:

A 26m

Explanation:

firstly the answer will not be part c as distance unit will be meters (m)

next, substitute the values of a and t as shown

\frac{1}{2}  (9.8)(2.3)^2 = 25.921

the answer rounded off to 2 significant figures will be hence 26m

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Read 2 more answers
A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student
castortr0y [4]

Answer:

5x10^-3

Explanation:

Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.

Hooke's Law can be represented as

<h3> F = kx, </h3>

<em>where F is the force </em>

<em>            k is the spring constant</em>

<em>            x is the extension of the material </em>

<em />

Plug values in the equation

Step 1 find the original extension

0.045 = (400)x

x = 1.125x 10^-4 m d

Step 2 find the new extension

0.045+2 = 400(x)

2.045 = 400x

x = 5.1125x10^-3

Step 3 subtract the new extension with original

Total extension of the spring =  5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3

8 0
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