An object travels a distance d with acceleration a over a period of time t according to the equation: d = at² After 2.3 seconds
with an acceleration of 9.8 m/s2, how far does an object travel (rounding the answer to two significant figures)?
1 answer:
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Answer:
1000 N
Explanation:
First, we need to find the deceleration of the running back, which is given by:
where
v = 0 is his final velocity
u = 5 m/s is his initial velocity
t = 0.5 s is the time taken
Substituting, we have
And now we can calculate the force exerted on the running back, by using Newton's second law:
so, the magnitude of the force is 1000 N.