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krek1111 [17]
2 years ago
8

An object travels a distance d with acceleration a over a period of time t according to the equation: d = at² After 2.3 seconds

with an acceleration of 9.8 m/s2, how far does an object travel (rounding the answer to two significant figures)?​

Physics
1 answer:
matrenka [14]2 years ago
5 0

Answer:

A 26m

Explanation:

firstly the answer will not be part c as distance unit will be meters (m)

next, substitute the values of a and t as shown

\frac{1}{2}  (9.8)(2.3)^2 = 25.921

the answer rounded off to 2 significant figures will be hence 26m

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Both A and B

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3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

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V = 3.6 V is the voltage applied

I = 2.6 A is the current

So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

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E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

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Solving for C, we find:

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5 0
2 years ago
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