Answer:
Oxygen, 43kg - Carbon, 16kg - Hydrogen, 7kg - Nitrogen, 1.8kg - Calcium, 1kg - Phosphorus, 0.78kg - Potassium, 0.14kg - Sulfur, 0.14kg - Sodium, 0.10kg - Chlorine, 0.095kg - and Magnesium, 0.019kg.
Answer:
Partial pressure for each of the three gases, in the mixture is 15 atm
Explanation:
Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.
Our total pressure = 45 atm
The 3 gases have the same pressure, so we can propose this equation:
3x = 45 atm
where x is the partial pressure for each of the three gases.
x = 45/3 → 15 atm
Im not sure what it is but i will try
BaCl₂(aq) + Na₂SO₄(aq) = BaSO₄(s) + 2NaCl(aq)
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) = BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
Ba²⁺(aq) + SO₄²⁻(aq)= BaSO₄(s)
Answer:
The presion is 0.6 atm
Explanation:
P1V1=P2V2
P2 = P1V1/V2
P2 = (4.00 atm * 0.30 L) / 2.0 L
P2= 0.6 atm
Answer:
Explanation:
H₂SO₄ is a strong acid, which means that most of it ionizes in aqueous solution.
Since it is a diprotic acid (two hydrogen ions) its ionization occurs in two steps:
- H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)
- HSO₄⁻ (aq) → H⁺(aq) + SO₄²⁻(aq)
Thus, almost all H₂SO₄ has ionized and its final concentration is almost nothing.
After the first ionization, the conentrations of H⁺(aq) and HSO₄⁻ are equal but by the second ionization more H⁺ ions are produced along with SO₄⁻.
You can show it as one step dissociation, assuming 100% dissociation (given this is a strong acid):
By the stequiometry you can build this table:
H₂SO₄ (aq) → 2H⁺(aq) + SO₄²⁻(aq)
Initial A 0 0
Change - x +2x +x
Equilibrium A - x 2x x
As explained, A - x is very low, and 2x is twice x. Thus,
The rank of the concentrations from highest to lowest is:
