Answer:
Explanation:
Sodium:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
Iron:
Fe₂₆= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
Bromine:
Br₃₅ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵
Barium:
Ba₅₆ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s²
Cobalt:
Co₂₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷
Silver:
Ag₄₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹ 4d¹⁰
Tellurium:
Te₅₂= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁴
Radium:
Ra₈₈ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ 7s²
I would say B) hawk and coyote.
Hope this helps!
Answer:
AlCl₃ + 3NaOH → 3NaCl + Al(OH)₃
Explanation:
Problem is to balance the given chemical equation:
Equation:
AlCl₃ + NaOH → NaClO₂ + Al(OH)₃
Balancing a chemical equation involves the conservation of atoms on both sides of the equation.
We can use a very simple mathematical method to balance the above equation;
aAlCl₃ + bNaOH → cNaCl + dAl(OH)₃
a, b, c and d are coefficients that will balance the equation:
Conserving Al: a = d
Cl: 3a = c
Na: b = c
O: b = 3d
H: b = 3d
Assume that a = 1;
c = 3
b = 3
d = 1
AlCl₃ + 3NaOH → 3NaCl + Al(OH)₃
O₂ in from of the NaClO₂ flouts the rule of chemical combination
