CO2
The symbol how you write
<span>molar mass of MgCl2
= 24.32 + 2 x (35.45) = 95.22 g</span><span>
<span>16.4g MgCl2 x (1 mol MgCl2/95.22
g MgCl2) = 0.172 mol MgCl2 </span>
</span>
<span>0.172 mol MgCl2 x (6.022 x 10^23/1 mol
MgCl2) = 10.36 x 10^22 atoms<span> </span></span>
Answer:
3.89 kg P2O5 must be used to supply 1.69 kg Phosphorus to the soil.
Explanation:
The molecular mass of P2O5 is
P2 = 2* 31 = 62
O5 = 5 *<u> 16 = 80</u>
Molecular Mass = 142
Set up a Proportion
142 grams P2O5 supplies 62 grams of phosphorus
x kg P2O5 supplies 1.69 kg of phosphorus
Though this might be a bit anti intuitive, you don't have to convert the units for this question. The ratio is all that is important.
142/x = 62/1.69 Cross multiply
142 * 1.69 = 62x combine the left
239.98 = 62x Divide by 62
239.98/62 = x
3.89 kg of P2O5 must be used.
