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iragen [17]
3 years ago
10

The Voyager 1 spacecraft, shown below, completed its space exploration mission in 1980 and has since been traveling away from Ea

rth at a speed of about 39,000 miles per hour.
If no unbalanced forces act on Voyager 1, then

A. the direction of its motion will reverse.
B. it will continue traveling at the same speed.
C. its speed will slowly decrease.
D. its speed will slowly increase.
Physics
2 answers:
Andreas93 [3]3 years ago
8 0

its b hope it helps

have a good day


aleksklad [387]3 years ago
4 0
I think b hope this helps
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When heat is removed from a substance , describe how the molecules are affected
kkurt [141]

I believe they would electron rate would slow down and the molecules would shrink.

I am almost positive that this is correct. I hope it helps!

6 0
3 years ago
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Suppose I have a vector that is 7 units long and that makes an angle of +30 degrees from the positive x-axis. I want to add to t
Vinil7 [7]

Answer:

sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j

Explanation:

We have given first vector which has length of 7 units and makes an angle of 30° with positive x-axis

So x component of the vector =7cos30^{\circ}=7\times 0.866=6.06

y component of the vector =7sin30^{\circ}=7\times 0.5=3.5

So vector will be 6.06i+3.5j

Now other vector of length of 7 units and makes an angle of 120° with positive x-axis

So x component of vector  =7cos120^{\circ}=7\times -0.5=-3.5i

y component of the vector =7sin120^{\circ}=7\times 0.866=6.06j

Now sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j

5 0
4 years ago
A labor push a crate through 12m and 720 J of work .The magnitude of force was
Harrizon [31]

Answer:

<h2>60 N</h2>

Explanation:

The magnitude of the force can be found by using the formula

f =  \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{720}{12}  = 60 \\

We have the final answer as

<h3>60 N</h3>

Hope this helps you

6 0
3 years ago
Which statement describes a unit rate?
Gwar [14]
Katherine paid $1.25 for a bottle of water
6 0
3 years ago
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A concert loudspeaker suspended high off the ground emits 33.0 W of sound power. A small microphone with a 0.600 cm2 area is 52.
Novay_Z [31]

Answer:

The sound intensity at the position of the microphone is 9.71\times10^{-4} W/m^{2}

Explanation

Sound intensity is given by the formula

I=\frac{P}{A}

Where I is the sound intensity, P is the power and A is the area.

Since the loudspeaker radiates sound in all directions, we have a spherical sound wave where the radius r is the distance of the microphone from the speaker.

∴ A is given by 4\pi r^{2} where r is the radius

From the question, P = 33.0W, r = 52.0m

I=\frac{P}{A} = \frac{P}{4\pi r^{2} }

I = \frac{33.0}{4\pi \times (52.0)^{2} }

∴ I = 9.71\times10^{-4} W/m^{2}

Hence, the sound intensity at the position of the microphone is 9.71 × 10⁻⁴ W/m²

7 0
3 years ago
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