Answer:
a

b

Explanation:
From the question we are told that
The speed of the airplane is 
The angle is 
The altitude of the plane is 
Generally the y-component of the airplanes velocity is

=> 
=>
Generally the displacement traveled by the package in the vertical direction is

=> 
Here the negative sign for the distance show that the direction is along the negative y-axis
=> 
Solving this using quadratic formula we obtain that

Generally the x-component of the velocity is

=> 
=>
Generally the distance travel in the horizontal direction is

=> 
=> 
Generally the angle of the velocity vector relative to the ground is mathematically represented as
![\beta = tan ^{-1}[\frac{v_y}{v_x } ]](https://tex.z-dn.net/?f=%5Cbeta%20%20%3D%20%20tan%20%5E%7B-1%7D%5B%5Cfrac%7Bv_y%7D%7Bv_x%20%7D%20%5D)
Here
is the final velocity of the package along the vertical axis and this is mathematically represented as

=>
=>
and v_x is the final velocity of the package which is equivalent to the initial velocity 
So
![\beta = tan ^{-1}[-130.05}{57.96 } ]](https://tex.z-dn.net/?f=%5Cbeta%20%20%3D%20%20tan%20%5E%7B-1%7D%5B-130.05%7D%7B57.96%20%7D%20%5D)

The negative direction show that it is moving towards the south east direction
Answer:
Explanation:
The angle between the polariser 1 and 2 is 60°
If I₁ be the intensity of light after polariser 1 , its intensity after polariser 2 that is I₂ can be expressed as follows
I₂ = I₁ cos² 60
= I₁ x 1/4
= I₁ x 
One eighth of a gram will remain
Answer:
4) True. The change of direction needs an unbalanced force
Explanation:
Let us propose the resolution of the problem using Newton's second law.
F = m a
As the car is spinning the acceleration is centripetal
a = v2.r
F = m v2 / r
We can see that as the velocity of a vector even if its module does not change, the change of direction requires an external force.
Now we can analyze the statement if they are true or false
1) and 3) False, even when the speed changes, the direction changes
2) False with the speed change can be determined
4) True. The change of direction needs an unbalanced force
5) False are different things. the direction is where it is going and the speed is the magnitude of the vector