Answer:
i think answer id leech because when it move it leave the liner
Mechanical energy E = mgh + 1/2mv²
When he starts, let h = 0 ⇒ E₁ = 1/2mv₁²
When he reaches height h ⇒ E₂ = mgh + 1/2mv₂²
Without friction, energy is conserved at all times.
E₁ = E₂
↓
1/2mv₁² = mgh + 1/2mv₂²
↓
1/2v₁² = gh + 1/2v₂²
↓
gh = 1/2(v₁² - v₂²)
↓
h = (v₁² - v₂²) / (2g)
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Answer:
doubled
Explanation:
<u>Step 1</u>. Linear momentum (p) = mass X velocity = mv
p = mv -----equation 1
<u>Step 2</u>. if the mass is now twice and speed is same
p = (2*m)v -----equation 2
solving equation 1 and 2 together,
p = mv = 2mv
p = 2
Therefore, its momentum is doubled
Time = 15/-0.5 = 14.5/-0.5 = 14.5s
The answer is 14.5s
Sorry no one would answer it sooner.
