When 6.0 L of He(g) and 10. L of N2(g), both at 0oC and 1.0 atm, are pumped into an evacuated 4.0 L rigid container, the final p
1 answer:
Answer:
P2=4atm
Explanation:
When 6.0 L of He(g) and 10. L of N2(g), both at 0oC and 1.0 atm, are pumped into an evacuated 4.0 L rigid container, the final pressure in the container at 0oC is
from boyle's law which states that the pressure on a gieben mass of gas is inversely proportional to the volume provided that temperature is kept constant
P∝1/v
PV=k
where k is the constant of proportionality
the v1=6L+10L=16L
P1=1atm
P2=?
V2=4L
16*1=4*P2
P2=4atm
P1=pressure 1atm
V1=volume of helium with nitrogen gas
P2=final pressure
V2=4l volume space
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Answer:
a = 3.125 [m/s^2]
Explanation:
In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.
where:
Vf = final velocity = 25 [m/s]
Vi = initial velocity = 0
a = acceleration [m/s^2]
t = time = 8 [s]
The initial speed is zero as the bus starts to koverse from rest. The positive sign of the equation means that the bus increases its speed.
25 = 0 + a*8
a = 3.125 [m/s^2]