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omeli [17]
3 years ago
6

Three quantum numbers for an electron in a hydrogen atom in a certain state are

Chemistry
1 answer:
OLga [1]3 years ago
6 0
It is option A 4s cause n=4, l=1 this is 4s orbital
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A 40.0-mL sample of 0.100 M HNO2 (Ka = 4.6 x 10-4 .) is titrated with 0.200 M KOH. Calculate: a. the pH when no base is added b.
In-s [12.5K]

Answer:

a) 2.173

b) 20ml

c) 3.87

d) 4.35

e) 8.8

f) 12.45

Explanation:

chech the attachment for explanationns

4 0
3 years ago
Given the equation representing a solution equilibrium: BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq)
goldenfox [79]

Answer:

The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases

Explanation:

Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in solution decreases significantly.

In this case, both BaSO4 and Na2SO4 both possess the SO4^2- anion. Hence SO4^2- anion is the common ion. Given the equilibrium;

BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq), addition of Na2SO4 will decrease the solubility of BaSO4 due to the presence of a common SO4^2- anion compared to pure water.

This implies that the equilibrium will shift to the left, (more undissoctiated BaSO4) hence decreasing the Ba^2+(aq) concentration.

3 0
3 years ago
Convert 0.881 mol N2 at STP to volume in liters ​
Vinvika [58]
The answers will be 21.5 L N2
7 0
3 years ago
Read 2 more answers
_____________________ are trying to create better batteries that can store more energy, so that electric cars can travel further
lidiya [134]

Answer:

options?

Explanation:

i mean scientists fits so if any of the options have a scientist thats it

8 0
2 years ago
Read 2 more answers
The mole fraction of a non-electrolyte (MM 40.0 g/mol) in a saturated aqueous solution is 0.310. What is the molality of the sol
jeka57 [31]

<u>Answer:</u> The molality of non-electrolyte is 24.69 m

<u>Explanation:</u>

We are given:

Mole fraction of saturated aqueous solution = 0.310

This means that 0.310 moles of non-electrolyte is present.

Moles of water (solvent) = 1 - 0.310 = 0.690 moles

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of water = 0.690 moles

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

0.690mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.690mol\times 18g/mol)=12.42g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}

Where,

n_{solute} = Moles of solute (non-electrolyte) = 0.310 moles

W_{solvent} = Mass of solvent (water) = 12.42 g

Putting values in above equation, we get:

\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m

Hence, the molality of non-electrolyte is 24.69 m

4 0
3 years ago
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