1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yan [13]
3 years ago
15

How I do this? and I need help like now!

Chemistry
1 answer:
Firdavs [7]3 years ago
6 0

Answer:

1ohm

Explanation:

You might be interested in
the elements iron (Fe), copper (Cu), and mercury (Hg) are classified as metals. which physical property of metals do they all sh
koban [17]

Answer:

They are heavy metals.

Explanation:

Heavy metals are generally defined as metals with relatively high densities, atomic weights, or atomic numbers.

6 0
3 years ago
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi
natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ....(1)

  • <u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:  

\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol

For the given chemical reaction:

2Fe(s)+O_2(g)\rightarrow 2FeO(s)

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = \frac{2}{2}\times 0.0771=0.0771mol of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:  

0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g

To calculate the percentage yield of iron (ii) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0
3 years ago
A student places a starch and water solution into a bag of dialysis tubing and then ties off the ends. Next, he places the fille
Zina [86]

Answer:

After 30 minutes have passed, the solution inside the dialysis tubing and the solution in the beaker will be tested for glucose and starch

-The presence of glucose will be tested with Benedict's solution, Testape®, or Clinistix

4 0
2 years ago
Which Of These Periods Contain Elements With Electrons s,p,d and f orbitals? Periods 1-3 Periods 1-4
Elanso [62]
The answer would be periods 6-7 :)
7 0
3 years ago
Other questions:
  • A sample of gas occupies 33 mL at -101 degrees Celsius. What volume does the sample occupy at 97degrees celsius? Plz help I have
    8·1 answer
  • The average density of whole milk is 1.034 g cm ^3. What is it’s density in lb gal ^-1?
    10·2 answers
  • What minimum concentration of clâ is required to begin to precipitate pbcl2? for pbcl2, ksp=1.17Ã10â5?
    5·1 answer
  • Part 2: Finding Speed and Height Using Energy Directions: Use the KE and GPE equations to solve for speed or height depending on
    15·2 answers
  • How many chromosomes would be in a sex cell of a Syrian hamster
    6·1 answer
  • What is the net force f⃗ net that the dipole experiences due to the electric field?
    7·1 answer
  • How would you balance the following equation NaOh + H2CO3=Na2CO3+H2O ?
    10·1 answer
  • Dl water will test<br> _________for protein?
    5·1 answer
  • 2Li+2H2O—&gt;2LiOH+H2
    11·1 answer
  • HELP HELP HELP HELP!!!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!