Q.1
a) 1 mol of N2 requires 3 moles of H2
so 4 moles of hydrogen will require = 4/3 = 1.33 moles
Answer of A) 1.33 moles
b) 2.5 moles of nitrogen gas were require to produce 5.00 moles of NH3
c) 7.5 moles of hydrogen gas were require to produce
5.00 moles of NH3
Q.2
a) 6 moles of H2 gas were require to make 6.00 mol H2S
b)24 moles of H2 gas were required to react with 3 moles of S8
c)56 moles of H2S are produced from 7 mol of S8
The volume of 0.175 M Na3PO4 solution that is necessary to completely react withn 95.4 ml of 0.102 M cuCl2 is
<u>calculation</u>
<u> </u><em> Step 1: </em> write the equation for reaction
3CuCl2 (aq) + 2Na3Po4 → Cu3(PO4)2 + 6 NaCl
Step 2 : find the moles of CuCl2
moles = molarity x volume in liters
volume in liters = 95.4 /1000 =0.0954 L
moles is therefore = 0.0954 L x 0.102 M= 0.00973 moles
Step : use the mole ratio to calculate the moles of Na3Po4
The mole ratio of CuCl2 : Na3PO4 is 3:2 therefore = 0.00973 x2/3= 0.00649 moles
Step 4 : find the volume of Na3PO4
volume = moles/molarity
= 0.00649 mole / 0.175=0.037 M
Explanation:
Molar mass of 
= 39.1 + 35.5 + 3(16.0) = 122.6 g
Molar mass of KCl = 39.1 + 35.5 = 74.6 g
Molar mass of 
= 32.0 g
According to the equation, 2 moles of reacts to give 3 moles of oxygen.
Therefore, 2 (122.6) = 245.2 g of will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of gives 96.0 g of oxygen.
(a) Calculate the amount of oxygen given by 2.72 g of as follows.
of
(b) Calculate the amount of oxygen given by 0.361 g of as follows.
of
c) Calculate the amount of oxygen given by 83.6 kg as follows.
of
Convert kg into grams as follows.
= 32731 g of
(d) Calculate the amount of oxygen given by 22.5 mg of as follows.
Convert mg into grams as follows.
of
