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3 years ago

What are atoms of an element with different numbers of neurons called?

Chemistry

2 answers:

den301095 [7]3 years ago

8 0

isotopes these are what they are called

uysha [10]3 years ago

5 0

The atoms of a chemical element can exist in different types. These are calledisotopes. They have the same number of protons (and electrons), but different numbers of neutrons.

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What should i do if i spill acid? ANSWER FAST PLEASE

Anna007 [38]

Answer:

If you spill an acid or base on your skin, immediately wash well with water. Strong bases react with the oils in your skin to produce a soapy feeling layer. Rinse until well after that feeling is gone. Do not attempt to neutralize a spill on your skin.

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2 years ago

Determine the number of HC=CH, monomeric units in one molecule of polyethylene with a molar

VladimirAG [237]

polyethylene contains HC=CH units.

mass of this is 26 gram/mol

number of such units =13500/26

3 0

3 years ago

How many atoms is 50 g of He?

tigry1 [53]

Atomic mass He = 4.002 u.m.a

4.002 g --------------- 6.02x10²³ atoms
50 g ------------------ ? atoms

50 x ( 6.02x10²³) / 4.002

= 3.01x10²⁵ / 4.002

= 7.52x10²⁴ atoms of He

6 0

3 years ago

Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) 2Hg (l) + O

diamong [38]

hey there!:

2HgO (s) => 2Hg (l) + O2 (g)

2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.

So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.

603 g of Hg = 603 / 200.6 = 3 moles

Percent yield = ( actual yield / theoretical yield) * 100

= ( 3/4) * 100

= 75 %

Hope this helps!

7 0

3 years ago

Read 2 more answers

when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc

OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =83.6g CO2

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0

3 years ago