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Fittoniya [83]
3 years ago
5

What are atoms of an element with different numbers of neurons called?

Chemistry
2 answers:
den301095 [7]3 years ago
8 0
<span>isotopes these are what they are called

</span>
uysha [10]3 years ago
5 0
<span>The atoms of a chemical element can exist in different types. These are calledisotopes. They have the same number of protons (and electrons), but different numbers of neutrons.</span>
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How many neutrons are in Cesium-130 (130/50 Cs)
Sergeeva-Olga [200]
 Best Answer:<span>  </span><span>Cross sections for formation of cesium and rubidium isotopes produced by bombardment of uranium with protons ranging in energy from 0.1 to 6.2 Bev were measured both radiochemically and mass spectrometrically. Independent yields were determined for Rb/sup 84/, Rb/sup 86/, Cs/sup 127/, Sc, su p 129/. Cs/sup 130/, Cs/sup 131/, Cs/sup 132/, Cs/sup 134/, Cs/sup 136/, and, at some e nergies, Rb/sup 83 and Cs/sup 135/. In addition, the independent yield of Ba/sup 131/ and the chain yields of Cs/sup 125/, Cs/sup 127/, Cs/sup 129/, La/sup 131/, Cs/sup 135/, Cs/sup 137/, ion cross sections of the Cs and Ba products on the neutron- excess side of stability decrease monotonically with increasing energy above 0.1 Bev, whereas the excitation functions for independent formation of the more neutron-deficient products in the Cs-Ba region and of Rb/sup 84/ and Rb/sup 86/ all go through maxima. The proton energies at which these maxima occur fall on a smooth curve when plotted against the neutronproton ratio of the product, with the peaks moving to higher energies with decreasing neutron-proton ratio. Under the assumption that the mass-yield curve in the region 125 < A < 140 is rather flat at each proton energy, the crosssection data in the Cs region can be used to deduce the charge dispersion in this mass range. Plots of log sigma vs N/Z (or Z--Z/sub A/) show symmetrical bell-shaped peaks up to a bombarding energy of 0.38 Bev, with full width at halfmaximum increasing from 3.3 Z units at 0.10 Bev to about 5 Z units at 0.38 Bev, and with the peak position (Z/sub p/) moving from Z/ sub A/ -- 1.44 to Z/sub A/ -- 0.85 over the same energy range. At all higher energies, a double-peaked charge distribution was found, with a neutron-excess peak centered at N/Z approximates 1,515(Z/sub p/ approximates Z/sub A/ -- 1.9), and having approximately constant width and height at bombarding energies greater than 1 Bev. The peak on the neutron-deficient side which first becomes noticeable at 0.68 Bev appears to become broader and shift slightiy to smaller N/ Z values with increasing energy, The two peaks are of comparable height in the Bev region, and the peak-to-valley ratio is only approximates 2. The total formation cross section per mass number in the Cs region decreases from approximates 52 mb at 0.1 Bev to about 29 mb at 1 Bev and then stays approximately constant; the contribution of the neutron-excess peak above 1 Bev is about 12 mb. The neutron-excess peak corresponds in width and position to that obtained in fission by approximates 50-Mev protons. The recoil behavior of Ba/sup 140/ lends support to the idea that the neutron-excess products are formed in a lowdeposition-energy process. The recoil behavior of Ba/sup 131/ indicates that it is formed in a high-deposition-energy process. Post-fission neutron evaporation is required for the observed characteristics of the excitation functions of the rubidium isotopes and the neutron-deficient species in the Cs region. The correlation between neutron-proton ratios and positions of excitation function maxima is semiquantitatively accounted for if fission with unchanged charge distribution, followed by nucleon evaporation, is assumed. (auth) 
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4 0
3 years ago
How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?
Naddik [55]
The solution for the question above is:

C = 0.270 
<span>V = 0.0275L </span>
<span>n = ? </span>

<span>Use the molar formula which is: C = n/V </span>
<span>Re-arrange it to: n = CV </span>
<span>n = (0.270)*(0.0275) </span>
<span>n = 0.007425 mols </span>
<span>(more precise) n = 7.425 x 10^-3 mols
</span>
7.425 x 10^-3 mols is the answer.
8 0
3 years ago
Be sure to answer all parts. Compounds a and b are isomers having molecular formula c5h12. Heating a with cl2 gives a single pro
Elden [556K]

Neo-pentane represents the Compound A while compound B is n-pentane.

After careful consideration we can say that compounds A and B are alkanes and also isomers of pentane. In chemistry, Isomers are defined as compounds having same empirical molecular formula but different structural formulas due to varying arrangement of atoms.

Now, as per the question statement, compound A gives a single monochlorination product upon heating with the molecule of chlorine i.e. Cl2 showing that the molecule is extremely symmetric. This molecule must be neo-pentane. Refer to image 1.

Similarly, Compound B forms 3 constitutional isomers after undergoing monochlorination. This compound must be n-pentane since three are 3 different types of carbon atoms in the structure. Refer to image 2.

If you need to learn more about neo-pentane click here:

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3 0
1 year ago
Read 2 more answers
After eating, nutrients must be oved to other parts of the body. Which of the following systems will transport these nutrients.
V125BC [204]
The circulatory system
4 0
2 years ago
Read 2 more answers
What type of reaction occurs without the addition of heat?
maria [59]

The type of reaction that occurs without the addition of heat is called spontaneous reaction. That is option D.

<h3>What is spontaneous reaction?</h3>

Spontaneous reaction is defined as the reaction where by new substances are formed naturally without the addition of extra energy in the form of heat.

Therefore, the type of reaction that occurs without the addition of heat is called spontaneous reaction

Learn more about heat here:

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5 0
2 years ago
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