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Fittoniya [83]
4 years ago
5

What are atoms of an element with different numbers of neurons called?

Chemistry
2 answers:
den301095 [7]4 years ago
8 0
<span>isotopes these are what they are called

</span>
uysha [10]4 years ago
5 0
<span>The atoms of a chemical element can exist in different types. These are calledisotopes. They have the same number of protons (and electrons), but different numbers of neutrons.</span>
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Sulfur and magnesium both have two valence electrons.<br> a. True<br> b. False
Nezavi [6.7K]
It would be false sulfur has 6 
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4 years ago
What is the term for a substance capable of dissolving another substance?
AURORKA [14]

Answer:

The answer to your question is: solvent

Explanation:

Solvent is a component in a solution that is present in the highest amount and is able to dissolve the other or others components.

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3 years ago
Is alcohol evaporating a chemical or physical change
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3 years ago
a. For the reaction 2H2 + 02→ 2H20, how many moles of water can be produced from 6.0 mol of oxygen? 2.0 mol b. 6.0 mol 12 mol d.
pickupchik [31]

Explanation:

from the equation 1 mole of O2 will give 2 moles of H2O then 6.0 moles of O2 will give x

6.0*2 moles/ 1 mole

= 12 moles

this implies that, 6.0 moles of O2 will give = 12 moles of water

3 0
3 years ago
The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react
Kazeer [188]

Answer:

The percent yield of  chloro-ethane in the reaction is 82.98%.

Explanation:

C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl

Moles of ethane = \frac{300.0 g}{30 g/mol}=10 mol

Moles of chlorine gases =\frac{650.0 g}{71 .0 g/mol}=9.1549 mol

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

\frac{1}{1}\times 9.1549 mol=9.1549 mol of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of  chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%

The percent yield of  chloro-ethane in the reaction is 82.98%.

6 0
3 years ago
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