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allsm [11]
3 years ago
9

What type of rays result in shorter days? (science)

Chemistry
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

verical rays

Explanation:

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Pcl5 exist but ncl5 does not.why?
jeyben [28]
N is as electronegative as Cl is. So Cl doesnt react with O, N
6 0
3 years ago
How many atoms are present in 2.1 moles of Fe
Lyrx [107]

Answer:

1.3 x 10²⁴ atoms Fe

Explanation:

To convert moles to atoms, you need to multiply your given value by Avogadro's Number. This causes the conversion to occur because Avogadro's Number exists as a ratio. It is the ratio that allows for the cancellation of units during multiplication. This is why atoms should be in the numerator of your conversion. The final answer should have 2 sig figs to reflect the given value.

Avogadro's Number:

1 mole = 6.022 x 10²³ atoms

2.1 moles Fe          6.022 x 10²³ atoms
---------------------  x  -------------------------------  =  1.3 x 10²⁴ atoms Fe
                                        1 mole

4 0
2 years ago
Explain in detail what happens when an acid and a base mix. Try to use the words ions, attraction, neutral and bonding in your a
Anton [14]

Answer:

when acid and the base mix it is bonding together and that makes it have a little blast but because of the acid

Explanation:

acid is the mane thing that makes 50% of things blast like as if i were to put baking soada and acid it would blast.  

Click the heart if this was helpful

5 0
3 years ago
What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E
yulyashka [42]

Answer: K_2SO_3.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = \frac{1.23}{0.63}=2

For S =\frac{0.63}{0.63}=1

For O =\frac{1.89}{0.63}=3

The ratio of K: S:O = 2: 1: 3

Hence the empirical formula is K_2SO_3.

7 0
3 years ago
Situation- I took time away from preparing for my Quiz competition to help two of my neighbourhood friends for their class exam.
blsea [12.9K]
Sorry I did not understand the question
3 0
3 years ago
Read 2 more answers
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