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allsm [11]
2 years ago
9

What type of rays result in shorter days? (science)

Chemistry
1 answer:
OLEGan [10]2 years ago
4 0

Answer:

verical rays

Explanation:

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In poor quality fireworks what will you notice and why
anastassius [24]
The best answer I could find was when you Google it, that the fuse is of poor quality. I cannot leave you a link, but you can find it for yourself. Put in poor quality fireworks and all sorts of things will pop up. No pun intended.
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Which choice below would affect the rate of reaction in the opposite way from the other four?
bulgar [2K]
Adding a catalyst as this would speed up the reaction and the rest would slow it down
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3 years ago
What is the mass of 4.56 moles of copper (ii) fluoride​
musickatia [10]

Answer:

463.0 g.

Explanation:

  • We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

7 0
2 years ago
What is the density of CHCL3 vapor at 1.00atm and 298K?
Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

PV=nRT

Number of moles (n)

can be written as: n=\frac{m}{M}

where, m = given mass

M = molar mass

PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT

where,

\frac{m}{V}=d which is known as density of the gas

The relation becomes:

PM=dRT    .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 298K

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

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3 years ago
In which of the following is the number of electrons the ion contains given correctly?
Agata [3.3K]

B. Cl- has 17 electrons.

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2 years ago
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